Q: A car moves 65 km due east then 45 miles due west What is its total displacement?

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5 miles minus 4 miles is 1 mile East of the starting point. Displacement is a vector quantity, so it must have magnitude and direction.

The total displacement is 8 km.

She has walked 23 miles, but her displacement is only 7 miles.

Draw a vector from his starting point to his ending point.

Distance 2+3=5 displacement 2

The resulting displacement can be found by using the Pythagorean theorem: (9 miles)^2 + (7 miles)^2 = c^2 81 + 49 = c^2 c = β130 Therefore, the resulting displacement is approximately 11.4 miles in a northeast direction.

No. Distance can be greater than displacement, but not less. The magnitude of the displacement between two points is also the minimum possible distance of a path between the same points.However, the displacement can be zero if the distance is not if the object's starting point and ending point are the same.

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Sarah's total displacement can be found using the Pythagorean theorem. The horizontal displacement is 20 yards east, and the vertical displacement is 50 yards north minus 50 yards south, which equals 0. This means her total displacement is the square root of (20^2 + 0^2) = 20 yards.

The overall displacement is the vector sum of the two displacements. Using the Pythagorean theorem, the displacement is β(1200^2 + 1500^2) = β(1440000 + 2250000) = β3690000 β 1921.32 m. The direction can be found using trigonometry as arctan(1500/1200) β 49.4 degrees north of east.

It is a total journey of 11 kilometres, resulting in a displacement of 5 km west.

How about you do your own homework, and in particular that which requires drawing which we can't do here, instead?I don't even think I could describe what to draw in terms any simpler than the question itself.