Q: 4 q in a fg

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steps to solve 4(3q-q): =(4)(3q+-q) =(4)(3q)+(4)(-q) =12q-4 answer: 8q

14x20

4(p + q), or 4p + 4q

It is Q*Q*Q*Q or Q^4 - whatever Q is.

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C f ef a g fg agf f a cd dc aa fg fg agf dd c f dc aa fg fg dc aa cd dc aa fg fg agf dd c f

-12q+4=q-6 4-6=q+12q -2=13q q=-2/13

The terms in a polynomial are seperated by a + or - So in given polynomial there are 4 terms.... abc , e, fg and h²

q=-4.

It is: 4*(q+p)

-q-11=2q+4 you would subtract 4 from both sides 4 and -4 cancel out and -11-4= -15 then you get -q-15=2q then you would add Q(1) to both sides (-q and q cancel out) then u get -15=3q thn u divide 3 to both sides (3 and 3 become q) then u get q=-5

4 x q=