Combustion reaction
When a candle burns, it undergoes combustion in the presence of oxygen to produce carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for this combustion reaction is: CxHy + O2 → CO2 + H2O.
The balanced equation for the reaction of C6H12O6 with O2 to form CO2 and H2O is: C6H12O6 + 6 O2 -> 6 CO2 + 6 H2O
Products of these are CO2, O2 and H2O Reactants of these are CO2, O2 and H2O (As they are the reverse of the other)
The balanced chemical equation for the combustion of butane (C4H10) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O
the answers is 6 _apex
The balanced equation is 8 O2 + C5H12 -> 5 CO2 + 6 H2O. So, the coefficient of O2 is 8.
H2O (water), CO2 (carbon dioxide) and N2 (nitrogen) are chemical compounds. O2 (oxygen) is a diatomic molecule, not a compound.
H2O, CO2, N2, O2, C6H11O6 H2O, CO2, N2, O2, C6H11O6
The balanced chemical equation for the reaction C2H6 + O2 → CO2 + H2O is: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
Triacontane is similar to candle wax (C25H52) and, when burnt, will produce CO2 and water vapour: 2 C30H62 + 91 O2 -> 60 CO2 + 62 H2O (For the algebraically-minded, the general formula for combustion of any hydrocarbon is: CxHy + (x+y/4) O2 -> x CO2 + y/2 H2O.) Incomplete combustion will produce a mixture of carbon, carbon monoxide, carbon dioxide and water - a bit more complicated! Combustion in air will produce oxides of nitrogen and potentially thousands of amines and other 'nasties'.