19 is opposite the 1 on a dartboard.
20 is the highest number, located at the top centre of the board.
121 is wrong. It is not possible to get 119 with two darts so how can 121 be the lowest score you cannot get with two darts. A lot of people think it's 99 due to the fact that it's the lowest number for which you need 3 darts to finish. But they forget that a treble is allowed for the 2nd dart. (99 = T19,T14) Also 101 = Bull + Treble 17 The answer is 103.
approximatly 1 and a half feet wide, all around.
The maximum from one dart is 60, (a treble 20)
Most people would say card monopoly (electronic)
19
I am not sure but i think it is 1 or 0 1/0
19
It's 103
In my opinion the 19 is directly opposite of the 1
Including the bulls eye, the numbers are 1-20.
20 is the highest number, located at the top centre of the board.
The Bullseye must be exactly 5 feet 8 inches from the floor and the toe line (where you stand to throw the darts) is 7 feet 9 and 1/4 inches from the board. Also see http://www.indepthinfo.com/darts/setup.shtml
-231. To get the opposite of a number, multiply it by -1.
The smallest number that you can't score with 3 darts, not including 1, is 4. With 3 darts, you can score any number from 3 (by hitting a score of 1 with each dart) up to 60 (hitting three triple 20s), but you cannot reach the score of 4 using the available scores on a dartboard.
When x is not zero, it can be (x + 1/x).
In the game of darts, a bogey number is a score that cannot be achieved with a combination of darts, specifically when aiming to finish a game. The common bogey numbers in standard play are 1, 2, and 3, as they cannot be scored with the standard dartboard configuration. Therefore, there are three bogey numbers in darts.