There are two nitrogen atoms in Aspartame. One is a primary N in R-NH3, while the other is a secondary N in R-NH-R (R represents the rest of the carbon structure). Since both N has three substituents in addition to the already present lone pair, they both have 4 groups attach to them. Thus, they are both sp3 hybridization.
These bonds are covalent.
A Krypton atom has 36 protons and 36 electrons each.
Bohr theory was introduced using hydrogen atom, it's not applicable to each and every atom, even for the other isotopes of hydrogen.
You are PROBABLY referring to the "Bohr Model" of the atom.
there is an equal number of positive and negative charges which exactly cancel each other out.
The central nitrogen atom in the molecule N2O has sp hybridization. Each nitrogen atom forms two sigma bonds with the oxygen atom, leading to a linear molecular geometry.
The nitrogen atoms in glycine are sp^3 hybridized. Each nitrogen atom forms three sigma bonds and one lone pair of electrons, resulting in a tetrahedral geometry around the nitrogen atom.
The hybridization of HCCl3 is sp3. Each carbon atom in the molecule is bonded to three chlorine atoms and one hydrogen atom, resulting in a tetrahedral geometry around each carbon atom, which corresponds to an sp3 hybridization.
The hybridization of MnO4- is sp3. Each oxygen atom contributes one electron to form single bonds with manganese, leading to the sp3 hybridization of the central manganese atom.
The molecule C4H8 has sp3 hybridization. Each carbon atom forms four sigma bonds with one another, resulting in the formation of a tetrahedral shape around each carbon atom.
The hybridization of CH3 is sp3. Each carbon atom forms four sigma bonds with hydrogen atoms, resulting in a tetrahedral geometry and sp3 hybridization.
Each nitrogen atom has 5 valence electrons.
The carbon in CH3CHCH2 has sp3 hybridization. Each carbon atom forms four sigma bonds, leading to the tetrahedral geometry characteristic of sp3 hybridization.
The silicon atom in SiBr4 has a hybridization state of sp3, forming four sigma bonds with the four bromine atoms. Each bond is formed by overlap between an sp3 hybrid orbital on the silicon atom and a p orbital on each bromine atom.
The hydrogens in propane are sp3 hybridized. Each hydrogen atom is bonded to a carbon atom, which forms four sigma bonds in a tetrahedral geometry, leading to sp3 hybridization for the hydrogens.
there are 7 protons in each nitrogen atom.
The hybridization of SiH4 is sp3, as the silicon atom utilizes its 1 s and 3 p orbitals to form four equivalent sp3 hybrid orbitals, each with a single hydrogen atom attached.