se and sometimes gain electrons.
Atoms with eight valence electrons do not easily lose electrons
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No, atoms do not bond to form electrons because electrons cannot be "formed" in this manner. Instead, bonds are formed when atoms share the electrons they possesses. Each atom wants to gain a full octet of electrons in its outermost shell. Until the atom has eight, it cannot be happy and remains "unstable." So, through the process of bonding, an atom will share its valence electrons (electrons in the outer shell) with another atom. This way, each atom can satisfy its octet and be happy.
Because the atoms having covalent bonds "share" the involved electrons equally. This is one of the effects of Quantum Mechanics, the shape of the orbital probability cloud containing the electrons in these bonds changes shape to encompass both atoms valence bands.
i really don't know so can someone answer it that knows
The valence electrons are the only electrons that are involved in chemical bonding. These electrons can be shared or transferred. A simple rule of thumb is that atoms "strive" to attain the octet either by loss gain or sharing of electrons.
No not if you mean gain to become a 5- anion. Possibly if you mean share 5 to become a covalent molecule. This is really a discussion about boron. There are a number of choices for boron, lose 3 to become B3+ , gain 5 to become B5-, share electrons to achieve the octet. B3+ and covalency look the best options. B3+ does not exist-- reasons the sum of the first 3 ionization potentials for B is high 6900kJ/mol (compared to Al with about 5000 kj/mol), B3+ if formed it would be really small and polarising- and an ionic bond would be impossible. Covalency is a good option, B will form 3 covalent bonds say with a chlorine or hydrogen and then needs an extra 2 say from a ligand with a lone pair such as Cl-, or H- to form tetrahedral anions