no of moles in Aspartame =mass/molar mass=1.2/294=0.00408mols
no of molecules=0.00408* avagadros no.=0.00408*6.022*10^23=0.02456*10^23
no. of atoms =no.of molecules*2(coz 2 atoms of nitrogen are present)=0.02456*10^23*2
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
The amount of hydrogen atoms that are present in 2.00 mg of aspartame are 2.167*10^22.
There are 17 micromoles in 5.00mg of aspartame. 5.00mg has a molecular weight of 294.303 g/mol. Aspartame is composed of carbon, hydrogen, nitrogen and oxygen. The chemical formula for aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. There are 6.022 x 10 ^23 molecules in a mole
That's the same as asking how many grams in a cup. There are 236.5 grams in a cup.
Nuetral nitrogen atoms have 7 protons and 7 electrons.
10 grams nitrogen (1 mole N/14.01 grams)(6.022 X 1023/1 mole N) = 4.3 X 1023 atoms of nitrogen ======================
The chemical formula for aspartame is C14H18N2O5. The molar weight is 294.3 grams/mol, so there are .00001699 moles of aspartame. Using Avogadro's number, there are 1.023 E19 molecules, each containing 18 hydrogen atoms. So there are 1.842 E20 atoms of hydrogen.
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
The amount of hydrogen atoms that are present in 2.00 mg of aspartame are 2.167*10^22.
the question is directing a discussion of Avagadro's number. If Nitrogen were an ideal gas ( it isn't) there would be 6,02 X 10 ^23 atoms
aspartame is a synthetic sweetening agent used in Pharmaceutical preparations and its Mol. Mass is 294.3 g/mol
The number of hydrogen atomst in 2,43 g of aspartame is 108,51285.10e23.
The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.
25 grams CONH22 (1 mole CONH22/64.196 grams)(1 mole N/1 mole CONH22)(6.022 X 1023/1 mole N) = 2.3 X 1023 atoms of nitrogen ======================
There are only nitrogen, oxygen atoms and no carbon atoms at all.
There are 17 micromoles in 5.00mg of aspartame. 5.00mg has a molecular weight of 294.303 g/mol. Aspartame is composed of carbon, hydrogen, nitrogen and oxygen. The chemical formula for aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. There are 6.022 x 10 ^23 molecules in a mole
15 grams of nitrogen are equal to 1,071 moles.