no of moles in Aspartame =mass/molar mass=1.2/294=0.00408mols
no of molecules=0.00408* avagadros no.=0.00408*6.022*10^23=0.02456*10^23
no. of atoms =no.of molecules*2(coz 2 atoms of nitrogen are present)=0.02456*10^23*2
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
The amount of hydrogen atoms that are present in 2.00 mg of aspartame are 2.167*10^22.
There are 17 micromoles in 5.00mg of aspartame. 5.00mg has a molecular weight of 294.303 g/mol. Aspartame is composed of carbon, hydrogen, nitrogen and oxygen. The chemical formula for aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. There are 6.022 x 10 ^23 molecules in a mole
That's the same as asking how many grams in a cup. There are 236.5 grams in a cup.
Nuetral nitrogen atoms have 7 protons and 7 electrons.
10 grams nitrogen (1 mole N/14.01 grams)(6.022 X 1023/1 mole N) = 4.3 X 1023 atoms of nitrogen ======================
The chemical formula for aspartame is C14H18N2O5. The molar weight is 294.3 grams/mol, so there are .00001699 moles of aspartame. Using Avogadro's number, there are 1.023 E19 molecules, each containing 18 hydrogen atoms. So there are 1.842 E20 atoms of hydrogen.
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
The amount of hydrogen atoms that are present in 2.00 mg of aspartame are 2.167*10^22.
To find the number of hydrogen atoms in 2.43 g of aspartame, calculate the number of moles of aspartame using its molar mass. Aspartame has a molar mass of 294.3 g/mol. Then, determine the number of moles of hydrogen atoms in one molecule of aspartame (the chemical formula of aspartame is C14H18N2O5). Finally, multiply the number of moles of aspartame by the number of moles of hydrogen atoms to find the total number of hydrogen atoms in 2.43 g of aspartame.
aspartame is a synthetic sweetening agent used in Pharmaceutical preparations and its Mol. Mass is 294.3 g/mol
the question is directing a discussion of Avagadro's number. If Nitrogen were an ideal gas ( it isn't) there would be 6,02 X 10 ^23 atoms
There are approximately 3.01 moles of urea in 25 g of CONH2, so there are 3.01 moles of nitrogen atoms. Therefore, there are 3.01 moles * 2 nitrogen atoms/molecule = 6.02 moles of nitrogen atoms in 25 g of CONH2, or urea.
There are 2 nitrogen atoms in 2NH3.
There are 17 micromoles in 5.00mg of aspartame. 5.00mg has a molecular weight of 294.303 g/mol. Aspartame is composed of carbon, hydrogen, nitrogen and oxygen. The chemical formula for aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. There are 6.022 x 10 ^23 molecules in a mole
15 grams of nitrogen are equal to 1,071 moles.
There are only nitrogen, oxygen atoms and no carbon atoms at all.