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To answer this question, the voltage to be used on the plug must be stated. With no voltage stated the answer is no. The smallest generator to obtain 50 amps is a 6000 watt generator.
The output of a 5600 watt or 5.6 kW generator in amperage using 240 volts is 5.6 x 1000 = 5600/240 x 1 = 23 amps.
Equation to use for single phase calculations is Amps = kW x 1000/Volts x pf.
For calculation purposes use 1 as a pf consonant. Generators that are commonly used in residential environments usually have a power factor of 1.0.
Amperage for each "hot" leg to neutral is 5600/120 x 1 = 46 amps. The only trouble using 120 volts is that on this type of generator, the 120 volt circuits are connected to the duplex receptacles. These receptacles are protected at 15 amps each.
You would need to have access to the generators junction box to change the generators output leads. Even then, all you will obtain is 46 amps.
A 6000 watt or 6 kW generator at 120 volts will give you 6000/120 x 1 = 50 amps.
A 12000 or 12 kW generator at 240 volts will give you 12000/240 x 1 = 50 amps.
Wiki User
∙ 9y ago
Wiki User
∙ 8y agoIf it's a 120 v system the generator is marginally adequate. If it's 240 v, no.
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How do you measure watts output of a generator?
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