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Suppose you want to add 11 and 12.instruction are : mvi a,11h mvi b ,12h mov d,b add b
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
because its an 8bit micro processor similar to those used in micro controller . capable of performing 16 bits double register calculations . something easy to start with
Suppose you want to add 11 and 12.instruction are : mvi a,11h mvi b ,12h mov d,b add b
An instruction is a command to the microprocessor to perform a given task on specified data. Each instruction has two parts: One is task to be performed,called the operation code (opcode). Second is the data to be operated on, called the operand. It can be specified in various ways,it may include 8bit/16bit data, an internal register, a memory location , or 8bit/16bit address. In some instructions, the operand is implicit. The 8085 instruction set is classified into three groups according to Word size. They are- 1. One word / 1 byte instructions 2. Ttwo word / 2byte instructions 3. Three word / 3byte instructions
8085 is a 8 bit microprocessor designed by Intel.
use two of them for 8 bits.
He does Let's Plays of Old and Recent 8bit and 32bit games.
32 bit
IPV4 is 32bit (4 times 8bit) rgds
so they fit correctly into an 8bit or 16bit slot
8-bit is a surrounding of a video game e.g. Mega Man. 8-bit is from the Atari Computer System.
One bit is 2 possible colors, black, 8bit has a possible of 256
8bit = 1 byte1024byte = 1kb1,024kb = 1mb1,024mb = 1gb1,024gb = 1tb