Stop getting answers for your webbie test
The coefficient of linear expansion DOES not depend on the length. Each material has a certain value for its coeeficient of linear expansion. The length of the material dictates how much it will expand linearly for a given rise in temperature. L" = L'(1 + a x (T'' - T')) That is the length at temperature T'' which is higher than temperature T' is given by the length L' at temperature T' multiplied by the quantity [1 + a x (T" - T')], where a is the coefficient of linear expansion which is constant for a given material. Thus if the temperature difference T" - T' is large then the expansion will be large which means L" - L' will be large. Likewise if the original length L' is large, then the corresponding expanded length L" will be large
Thermal expansion is the change in the size of an object or structure due to the increase in atomic bond lengths at higher temperatures. That's what it comes down to. A steel railroad rail is set with a small gap between it and the next rail so linear expansion won't cause the rails to push against each other and the track to buckle. Large skyscrapers have their exterior skins engineered so that thermal expansion won't cause the aluminum, steel or other trim to buckle and pull away from the structure. Keep in mind that this is a 3D problem and not just a 2-dimensional one (though in the case of the rails, the third dimension isn't nearly as important. We are talking about a thermodynamic property of materials. The coefficient of thermal expansion is a measure of that change in length or volume of a material as a function of temperature. It's just that simple. As objects get warmer, their size increases by "x" amount. And this may not be linear, too. At higher temperatures, there may not be as much of an increase in the "size" of an object for another identical change in temperature. There are some measurements and some calculations that must be made to come up with the numbers. More information can be found by using the link below to the Wikipedia article on the coefficient of thermal expansion.
The machine has to leverage the original force in such a way as to multiply it.
The volume of a sphere is 4/3 pi R3, which shows that volume is proportional to the cube of the linear dimension. Alternatively, the linear dimension is proportional to the cube-root of the volume.If volume decreases by a factor of 27, diameter decreases by a factor of (cube-root of 27) = 3. Diameter becomes 1/3rd the original diameter.
Positive Temperature coefficient indicates that the resistance of material INCREASES with rise in the temperature. Resistance Temperature COefficient(RTC) is defined as increase in resistance per unit original resistance per unit rise in temperature. Temperature Coefficient of Resistance=R2-R1/(R1*(T2-T1)) Where: R2:Resistance at temperature T2 R1:Resistance at temperature T1 SO from formula it is clear that if resistance increases with temperature(T2-T1>0 and R2>R1) then Difference R2-R1 will be positive hence RTC will have positive value. But if with increase in temperature(T2-T1>0) resistance decreases(R2<R1) then difference R2-r1 will be negative hence RTC will be negative.
yes,according to relation coefficient of linear expansion depends upon original length.
Yes, they do. The phenomenon is called thermal expansion. Every substance has a "coefficient of expansion" figured out via experiment. The coefficient is used in the following way. change in length = original length * change in Temperature (K) * coefficient of linear expansion change in volume = original volume * change in Temperature (K) * coefficient of volume expansion The coefficient of volume expansion is three times the coefficient of linear expansion. The unit for the coefficient is "per degree" (this makes more sense when you use it in an equation)
Not true. The expansion will have one more term.
100 times its original size. your welcome!
The coefficient of linear expansion DOES not depend on the length. Each material has a certain value for its coeeficient of linear expansion. The length of the material dictates how much it will expand linearly for a given rise in temperature. L" = L'(1 + a x (T'' - T')) That is the length at temperature T'' which is higher than temperature T' is given by the length L' at temperature T' multiplied by the quantity [1 + a x (T" - T')], where a is the coefficient of linear expansion which is constant for a given material. Thus if the temperature difference T" - T' is large then the expansion will be large which means L" - L' will be large. Likewise if the original length L' is large, then the corresponding expanded length L" will be large
dL/dT = αL*L, where L is the length of the steel, T is temperature, and αL is the linear thermal expansion coefficient which for steel is about 11.0 to 13.0. That is possibly the easiest differential equation in history: (1/L)dL = (αL)dT ln(L) = αLT L = eαLT
Coefficient of Linear thermal expansion (CLTE) = Alpha Alpha=(change in length)/(original length*change in temp) =Meters/(meters*Celsius) =m/mC (meters cancel leaving...) =1/C =C^-1
Either the question is misworded, or more information is needed. Compression implies load; in order for a peice of metal to be loaded by a temperature change, it would need to be rigidly restrained by something with a different coefficient of thermal expansion. If you mean what is the dimensional change, that is answerable. It is as follows: (original size) X (coefficient of thermal expansion) X (temperature difference) = (change in length) You need to look up the coefficient of thermal expansion, and make sure you get the units right: /°C or /°F
nominal diameter is the original diameter of an object
You cant, you must have an original sims game to install a expansion pack.
They are supposed to be different. They add on to the game. You cannot use expansion packs without the original game.
When the bimetallic strip cools down, the metals in the strip contract at different rates due to their varying coefficients of thermal expansion. This differential contraction causes the strip to bend, with the side of the metal with higher expansion coefficient (usually the inner layer) being on the inside of the curve.