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When you treat silver chloride with excess ammonia solution, Diamine silver (I) chloride is formed . The reaction involved is- AgCl + NH(3) --->Ag( (NH(3)) 2)(+) + Cl(-).

What you will observe is that AgCl is insoluble, but after adding ammonia it becomes soluble because of above reaction.

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8y ago
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3y ago

AgCl dissolves

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Q: What would be observed when a fresh precipitate of silver chloride is treated with excess ammonia solution?
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