If your power source is 120 V then 8000/120 = 66.7 Amps. If operated at 240 V then it is 33.3 Amps. In the first case you would need 3 AWG and in the second 8 AWG.
The formula you are looking for is I = W/E.
The formula you are looking for is I = W/E, Amps = Watts/Volts. Amps = 5000/230 =21.7 amps. The wire size to run this heater would be a #10 copper conductor. The supply breaker would be a two pole 30 amp breaker.
The cable that is used to connect from the generator is based on the size in kW's of the generator and the generator's breaker size rated in amps. It usually is a flexible cab-tire 4 wire cable if the generator is a portable type. If it is a stationary generator is has to be wired with a flexible conduit so as not to transmit vibration from the generator to the conduit system.
The heater element is a coiled wire resistor that draws enough current to supply the intended amount of power, which might be 1.5 - 3 kW. Quickly the temperature of the wire rises until it reaches an equlibrium where the heat power conducted away by convection is the same as that draw from the power supply.
This question can't be answered because it depends on the heater. Read the plate on the heater; it might be put where it's not easy to see but it should be there. The plate may tell you the current drawn, but it's more likely to tell you the consumption in Watts, or kiloWatts, from which you can easily calculate what breaker you need. <<>> A normal electrical hot water tank that is used in North American homes will use a two pole 20 amp breaker. This will handle a tank rated up to 4800 watts.
A breaker protects the wire size of the feeder that is connected to it. The amperage of the load must be found. Without a voltage stated the amperage from the wattage given can not be calculated. The equation for amperage when the kw is given is A = kW x 1000/1.73 x volts x pf. The pf constant to use is .9.
The formula you are looking for is I = W/E.
AWG #3 copper.
The formula you are looking for is I = W/E, Amps = Watts/Volts. Amps = 5000/230 =21.7 amps. The wire size to run this heater would be a #10 copper conductor. The supply breaker would be a two pole 30 amp breaker.
The use of a breaker in a circuit is to protect the wire size used in the circuit from becoming overloaded. Using the wattage of the load does not help for breaker sizing because the breaker operates on amperage. Amperage can be found from wattage by using the following equation. I = W /E. Amps = Watts / Volts. As you can see the amperage can not be calculated because there is no voltage stated.
Yes, the total amperage load of a 2000 watt heater at 240 volts is 8.3 amps. Keep in mind that the wire feeding the heater must be a #10 because the breaker is rated at 25 amps. A wire's ampacity rating can be larger that the breaker amperage rating but never smaller. Example, a #14 rated at 15 amps or a #12 rated at 20 amps can not be connected to a 25 amp breaker. The 25 amp breaker does not trip until it reaches 25 amps well over the allowable amperage of the #14 amd #12 wire. This is why a #10 wire must be used as its rating is 30 amps.
10 kW at 220v will use 45.45 Amps. I'd recommend a 60A circuit, with a 60A breaker, but the heater or electric furnace should have "maximum fuse amps" rated on its nameplate. Above all, neverconnect wiring to a breaker that is rated higher than the maximum current capacity of the wire. In the case of 60A, use #6 AWG wire.The HVAC Veteran
To answer this question the voltage of the system is needed.
To answer this question the output voltage of the generator must be stated. Breakers are sized to protect the wire that is connected to it. Wire is sized by the amperage that it can carry. Once the voltage is stated use the following equation Amps = kW x 1000/1.73 x Volts x pf. for three phase and Amps = kW x 1000/Volts x pf. In both cases use .9 for a power factor value.
I=270000/380/1.732 I=410A USE: 500A CIRCUIT BREAKER
the given kw Divide by the your voltage
This formula will give you the amperage I = kw x 1000/1.73 x E x pf (pf = power factor). Take the amperage and multiply it by 125%. This will give you the breaker size that you need.