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This would be a double displacement reaction. This reaction will happen since there is a insoluble substance(solid) being formed which would be Sr(OH)2. The equation would be:

NaOH(aq) + Sr(NO3)2(aq) ---> NaNO3(aq) + Sr(OH)2(s)

Then you balance it:

2NaOH(aq) + Sr(NO3)2(aq) ----> 2 NaNO3(aq) + Sr(OH)2(s)

(aq) = aqueous solution.

(s) = solid

All Nitrates are soluble (NO3)-.

Hydroxides (OH)- are insoluble with the exceptions (salts of NH4 and alkali metals, which is group 1A).

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Q: What precipipate will form from Sodium hydroxide plus Strontium nitrate?
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