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The answer is 2,107749515.1025 molecules.
Leonel Marvin
Wiki User
∙ 8y agoEach mole of NH3 contains 1 mole of N. 35 grams N2 x 1mol N2/28g = 1.25 moles of N2 = 2.5 moles of N. This will make 2.5 moles NH3 (given sufficient H2 gas). The mass of NH3 would be
2.5 moles x 17 g/mole = 42.5 grams.
Hannah Fradette
Michael Brown
Wiki User
∙ 13y agoAvogadro's number, N, is the number of particles in one mole of a substance. N is approximately equal to 6.02 * 1023. This value is constant; it applies to the number of particles in any substance.
# of molecules = N * n (where n is the number of moles)
# of molecules = 6.02 * 1023 molecules/mole * 35 moles
# of molecules = 2.107 * 1025 molecules
Wiki User
∙ 9y agoMultiply 35 by Avagadro number.Avagadro number is 6.022*10 (23)
Wiki User
∙ 9y agoThe answer is 2,107749515.1025 molecules.
Wiki User
∙ 8y agoThe answer is 42,55 g.
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How many grams of NH3 can be produced from 2.08 grams of N2?
Ok, so I'm assuming that the chemical formula is written as - 3H2 + N2 ----> 2NH3 2.80 = moles of N2 17.03052 g/mol = Molar mass of NH3 (2.80 mol N2) x (2 NH3) / (1 N2) = 5.6 mol NH3 x (17.03052 g) / (1 mol NH3) = 95.4 g NH3
Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?
16,45 g nitrogen are needed.
How many grams of ammonia NH3 will produce 300 grams of N2?
394.794 grams
How many grams of H2 are needed to produce 10.06 g of NH3?
The formula reaction for NH3 when using N2 and H2 is: (N2)+3(H2) ---> 2(NH3) Now, first step is to find the moles of the H2 reactant. This is found via (grams of reactant)/(molar mass of reactant). There are 10 grams, and the molar mass of H2 is approximately 2.016. Therefore, the equation should look like: 10/2.016. This yields a value of ~4.9606 moles of H2. Now, you use the molar ratio from the reactant to the product to determine how many moles of product were yielded. According to the reaction, three moles of H2 are required to produces 2 moles of NH3. So, the mole ratio is 2/3. Multiply the number of moles of H2 with the molar ratio to determine the moles of NH3. 4.0606 * 2/3 = 3.3071 moles of NH3. Multiply the number of moles with the molar mass of NH3 (17.0306), and voila! 3.3071 * 17.0306 = 56.3216 grams. Now, if your teacher is feeling like a stickler about significant figures, than that value should be rounded to 56 grams of NH3.
What is the molar mass of (NH3)2SO4 in grams?
Maybe you meant (NH4)2SO4 because not sure (NH3)2SO4 exists, but the answer to the question as written would be:(NH3)2SO4 has 2N, 6H, 1S and 4O2N = 2x14.0 = 28.06H = 6x1.0 = 6.01S = 1x32.1 = 32.14O = 4x16.0 = 64.0Add them up to get 130.1 g/mole
100 grams of ammonia equals how many moles?
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
What is mass of ammonia?
The molecular mass of ammonia (NH3) is 18.03 grams/mole
What is the mass in grams of 1.20x1025 molecules of ammonia NH3?
The mass of ammonia is 339,7 g.
How do you calculate the mass in grams of 4.2 x 1025 NH3?
Molecules of ammonia? Will assume so. 4.2 X 1025 molecules NH3 (1 mole NH3/6.022 X 1023)(17.034 grams/1 mole NH3) = 1188 grams of ammonia ===================( could call it 1200 grams NH3 for significant figure correctness )
Calculate mass in grams of 2.110 moles of NH3?
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
How many grams are their in 3.4x10molecules of NH3?
The mass is 9,6.10e-22 g for 34 molecules.
What is the mass of 0.500 mol of NH3?
NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.
How many moles are in 4.00g of NH3?
molar mass=NH314+3=17moles=give mass /molar mass400 / 17=23.5294
How many grams of NH3 can be produced from 2.79 moles of N2?
The mass of ammonia will be 95,03 g.
How many grams of NH3 can be produced from 4.33 mol of N2 and excess H2. Express your answer numerically in grams.?
The mass of ammonia is 147,5 g.
How many mole are represented by 5.67 grams of CO 2 and 25.45 grams of NH3?
5.67g of CO2 divided by 44g/mol (CO2's molar mass) gives you 0.129 moles. 25.45g of NH3 divided by 17g/mol (NH3's molar mass) gives you 1.497 moles. To get the molar mass, visit the periodic table and add up the numbers of each constituent element.
