Milky Yellow
The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
The question statement is true (except that the first instance, but not the second instance, of "dissolved" is misspelled.)
The formula unit for the formation of potassium chloride and barium sulfate is one mole. One unit of potassium sulfate and barium chloride are required for the reaction.
Since barium chloride is reactive with sulfate ions there would be more precipitate present. The solution with more precipitate present would show it had higher amounts of sulfate ions
barium hydroxide
K2CrO4 + BaSo4 ----------> BaCrO4 (Precipitate) + K2SO4 Potassium Barium Barium Potassium Chromate Sulphate Chromate Sulphate It Is A Double Displacement Reaction
A solution of barium chloride is added to a solution of potassium chromate, a yellow precipitate forms.
The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
balance equation of barrium chloride to sodium chromate
it turns into potassium nitrate and barium chromate K2CrO4 + Ba(NO3)2 --> 2KNO3 + BaCrO4
The question statement is true (except that the first instance, but not the second instance, of "dissolved" is misspelled.)
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.
It forms a precipitate called sodium chloride and barium hydroxide, which both are colourless.
The formula unit for the formation of potassium chloride and barium sulfate is one mole. One unit of potassium sulfate and barium chloride are required for the reaction.
Nothing - barium chloride is soluble. You can however precipitate either the barium (e.g. with sodium sulphate, giving barium sulpate, or the chloride, e.g. with silver nitrate giving silver chloride precipitate.
Since barium chloride is reactive with sulfate ions there would be more precipitate present. The solution with more precipitate present would show it had higher amounts of sulfate ions
You can attempt to pass the gas into aqueous acidified potassium manganate(VII). Sulfur dioxide turns it from purple tocolourless.It forms a white precipitate of barium sulphate when passed through a solution of barium chloride and chlorine water.