To calculate the peak voltage of an RMS voltage in a sine wave simply multiply the RMS voltage with the square root of 2 (aprox. 1,414) like this:
240 x 1,414 = 339,4 V
RMS x sqr.root of 2 = peak voltage
48root2
339.4625
No, the peak-to-peak voltage is 2sqrt(2) times as much as the rms for a pure sine-wave.
4volts x 2.8 =9.6 v
If the Peak to neutral voltage is 220 volts, the root mean square voltage is 155.6 volts (sqrt(220)).
A: peak B: sine C: square D: linear
The quoted value is usually RMS value, i.e it is lesser than the peak value of the voltage, therefore the peak value is sqrt(2) times the quoted value. (it is a sine wave)
the answer is 5.6vp-p
Assuming sine wave (it is different if not): Vp-p = 2.828 * Vrms
For a sine wave, the form factor is the square root of 2. Thus, the effective voltage of 56 V (56 Vrms) is 2-1/2 times the peak-to-peak voltage. Thus, the peak-to-peak voltage Vpp = Vrms * sqrt(2)In this example:Vpp = 56V * 1.4142... = 79.2V (rounded to one decimal place)
It is the 'as if' voltage in an AC circuit. Referred to as Vrms 120 volts in your house is Vrms, the effective voltage, 'as if' it were DC 120V, can do the same work. But 120VACrms is a sine wave with a peak voltage much higher than 120 volts.
RMS means root mean square of a sinusoidal wave form and the number that describe it is .741 of the peak average is ,639 of the peak
No, the peak-to-peak voltage is 2sqrt(2) times as much as the rms for a pure sine-wave.
238
if that 144 is the peak voltage if its a sine wave the rms voltage is that voltage divided by sqrt(2) if not a sine wave (modified) you must find the area under the curve by integrating a cycle of that wave shape (root mean squared)
4volts x 2.8 =9.6 v
The RMS (root mean square) of the peak voltage of a sine wave is about 0.707 times the peak voltage. Recall that the sine wave represents a changing voltage, and it varies from zero to some positive peak, back to zero, and then down to some negative peak to complete the waveform. The root mean square (RMS) is the so-called "DC equivalent voltage" of the sine wave. The voltage of a sine wave varies as described, while the voltage of a DC source can be held at a constant. The "constant voltage" here, the DC equivalent, is the DC voltage that would have to be applied to a purely resistive load (like the heating element in a toaster, iron or a clothes dryer) to get the same effective heating as the AC voltage (the sine wave). Here's the equation: VoltsRMS = VoltsPeak x 0.707 The 0.707 is half the square root of 2. It's actually about 0.70710678 or so.
12.68V 3o * sin25 = 12.67854785
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.