1.002 M
The molarity is 0,41 mol/L.
Magnesium sulphate: MgSO4.7 H2O
Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose
Mg3N2 + MgO + 4H2O --> 4MgO + H2O + 2NH3
I suppose that this situation is not possible.
The molarity is 0,41 mol/L.
You dissolve it in water, and the partial charges of H2O should rip CaCl2 apart into Ca2+ ions and Cl- ions.
This means that there are two bromines in magnesium bromide, much like there are two hydrogens in water, H2O. This occurs because when magnesium forms an ion it has a charge of (+2), and when bromine forms an ion, it has a charge of (-1), Thus, it takes 2 bromines to neutralize the charge of the magnesium.
Magnesium oxide is a base because it can produce hydroxide ions in solution. (The definition of a base by Bronsted-Lowry is that it is a proton (that is, a hydrogen ion, because hydrogen ions have no neutron and have lost their electron, so they are just left with a proton) acceptor. MgO+H2O ---- Mg+2OH Therefore, it produces hydroxide ions in solution.
no magnesium doesn't react with pure H2O
Magnesium sulphate: MgSO4.7 H2O
Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose
That is magnesium sulfate hydrate.
Magnesium is the correct spell....Whatever, if you add Magnesium (Mg) to Water (H2o), it will form Magnesium Hydroxide. The following equation is:- Mg+O2+H2O=Mg(OH)2
Mg3N2 + MgO + 4H2O --> 4MgO + H2O + 2NH3
Water (H2O)
Water: H2O molecules, H+ and OH- ions