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What is the angular momentum of a 0.210kg ball rotating on the end of thin string in a circle of radius 1.10m at angular speed of 10.4 rad's?
Wiki User
∙ 10y ago
What we've got here is a particle rotating around an axis some distance from
it. So its angular momentum is ( r X m v ), and the fact that the particle
happens to be a ball is irrelevant.
The vector cross-product just says that the direction of the angular momentum
vector will be perpendicular to the plane of the rotation, which I don't think we care
about for purposes of this question. We're just looking for its magnitude . . . r m v .
r = radius of the rotation
m = mass
v = speed around the circle = ( ω r )
r m v = (r m) (ωr) = m ω r2 = (0.210) (10.4) (1.1)2 = 2.64264 kg-m2/sec
I have no feeling for whether or not that's a reasonable result. I lost it around
the last time I had to calculate an angular momentum ... an event that was
roughly contemporaneous with the mass extinction of the dinosaurs.
Wiki User
∙ 10y ago
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the angular momentum is given by:.L = mass (m) * velocity (v) * radius (r)you have the mass and radius, so to calculate the velocity:.circumference = 2 * pi * r = 2 * 3.1416 * 0.95 = 5.969 metres14.7 rad / sec = 2.3396 rev / secso velocity = circumference * rev / sec = 2.3396 * 5.969 = 13.965 metres / sec.so:.L = m * v * r = 0.73 * 13.965 * 0.95 = 9.685 n-m-s
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Does the blade of a fan that is turned on have angular momentum?
yeah,bcoz it moves in circle around a specific point.
An electric ceiling fan is rotating about a fixed axis with an initial angular velocity of 0.300 The angular acceleration is 0.898 Its blades form a circle of diameter 0.760?
What do you want to know about it?
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What is the angular momentum of a 0.730 kg ball rotating on the end of a thin string in a circle of radius 0.950 m at an angular speed of 14.7 rad per second?
the angular momentum is given by:.L = mass (m) * velocity (v) * radius (r)you have the mass and radius, so to calculate the velocity:.circumference = 2 * pi * r = 2 * 3.1416 * 0.95 = 5.969 metres14.7 rad / sec = 2.3396 rev / secso velocity = circumference * rev / sec = 2.3396 * 5.969 = 13.965 metres / sec.so:.L = m * v * r = 0.73 * 13.965 * 0.95 = 9.685 n-m-s
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When does a uniform circular occur?
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How many degrees of angular measurement are the in a circle?
360
