Dear Wiki Questioner,
To calculate the kinetic energy of an object, we use the following equation:
KE=(1/2) m v^2
Where KE is the object's kinetic energy in Joules
m is the object's mass in kilograms
and v is the object's velocity in meters per second
So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation:
25g (1 kg/ 1000 g) = .025 kg
The mass of the bullet is .025 kilograms!
Now we plug the numbers into the equation and solve:
KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J
So the kinetic energy of your bullet is 3125 Joules
kinetic energy
it has both potential and kinetic energies as when it is going upwards, the potential energy increases while the kinetic energy decreases until it reaches the top, and then the kinetic energy is zero and the potential energy is maximum.
The momenta of the rifle and the bullet are equal and opposite. The bullet has greater kinetic energy than the rifle.
A bullet racing by a non moving observer has kinetic energy.
A speeding bullet has a ton of kinetic energy.
A bullet racing by a non moving observer has kinetic energy.
Kinetic energy and sound energy.
The kinetic energy of the speeding bullet is converted to heat and sound energy.
A high kinetic energy, combined with a small cross section.
Kinetic Energy
When a bullet is fired from a rifle, a chemical reaction in the gunpowder ignites, rapidly expanding gases build up pressure, and the bullet is propelled out of the barrel at high speed. The rifling in the barrel causes the bullet to spin, improving accuracy and stability. Gravity will eventually cause the bullet to drop due to gravity and air resistance.
The kinetic energy of a 22500 lb truck traveling 55 mph is 1/2mv2 is 3084.808kJ.