Add a solution of magnesium chloride; magnesium hydroxide is not soluble in water.
SO42-
Only Ba2+ and SO42- react, while Na+ and Cl- don't.Ba2+ + SO42- --> (BaSO4)s
Potassium and nitrate don't react, stay unchanged as hydrated ions in solution, called spectator ions. Only sulfate and barium ions react by precipitating to solid. (SO42-)aq + (Ba2+)aq --> (BaSO4)s :)
You didn't provide an ion. So since it's a positive most likely a negative ion.
Since iron (Fe) is more reactive than copper (Cu) it will be 'plated' with copper when the metal iron is stuck in copper sulfate solution. Fe(s) + Cu2+(aq) + [SO42-]aq ---> Fe2+(aq) + Cu(s) + [SO42-]aq
Firstly add some AgNO3. You should see that no precipitate forms. If it forms a precipitate, it is not a SO42-.Then add some BaCl2 - If there are SO42- ions a white precipitate will form.
SO42-
Only Ba2+ and SO42- react, while Na+ and Cl- don't.Ba2+ + SO42- --> (BaSO4)s
Potassium and nitrate don't react, stay unchanged as hydrated ions in solution, called spectator ions. Only sulfate and barium ions react by precipitating to solid. (SO42-)aq + (Ba2+)aq --> (BaSO4)s :)
NH4+ and Cl- don't react, Only SO42- and Ba2+ do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
The immediate response is a milky appearance. After 5-10 minutes a precipitate of BaSO4 will settle out of solution. You will obtain a cloudy, white precipitate that will remain so infantily. This is a precipitation reaction (the formation of an insoluble salt from a solution of soluble ones) which occurs because barium sulfate is insoluble, so when mixed, the barium ions react with the sulfate ions to form a white precipitate of barium sulfate The net ionic equation is: Ba2+(aq) + SO42-(aq) ----> BaSO4(s)
NH4+ and NO3- don't react, Only SO42- and Ba2+ do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
add barium chloride or barium nitrate to a solution containing sulphate ions SO4 2-. To the same solution add hydrochloric acid in excess. OBSERVATIONS, a white precipitate which is insoluble in excess acid confirms presence of SO42- IF IT DISSOLVES then it confirms SO32- ----------------------------------------- 1) Add barium nitrate solution under acidic conditions (use an equal volume of hydrochloric acid) to the unknown solution 2) A white precipitate of barium sulphate forms if sulphate ions are present
So42- + 4H+ + 2e- goes to SO2(g) + 2H20(I)
So42- + 4H+ + 2e- goes to SO2(g) + 2H20(I)
There is not a special test for negative ions IN GENERAL. However there are many possibillities for negative ions of each kind in particular: Example: test on Cl- : add silver nitrate: AgCl precipitate test on S2-: add drop of dilute acid: smell of rotten eggs (H2S) test on SO42-: add BaCl2 solution: BaSO4 precipitate
You didn't provide an ion. So since it's a positive most likely a negative ion.