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What are the two methods of actually subtracting 8.5 from 89.5 entirely in Roman numerals showing work?
Wiki User
∙ 11y ago
Notwithstanding todays modern usage of Roman numerals inasmuch that there is undisputed historical evidence to confirm that the ancient Romans would have subtacted the equivalent of 8.5 from 89.5 using either one of the following formats:-
SXC-SIX = XXCI => (100-10.5)-(10-1.5) = (101-20)
Remember that a double minus in arithmetic becomes a plus
Alternatively by cancelling out same numerals:-
LXXXVIIIIS-VIIIS = LXXXI => 89.5-8.5 = 81
Note that XXCI is an abridged version of LXXXI thus using less numerals but of equal value.
Individual values: C=100, L=50, X=10, V=5, I=1 and S=0.5 or 1/2
Accumlative values: 2*S=I, 5*I=V, 2*V=X, 5*X=L and 2*L=C
Todays modern rules governing the Roman numeral system were compiled and intoduced during the Middle Ages but this was well over a thousand years later after the foundation of the Roman Empire.
QED by David Gambell
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∙ 11y ago
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