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What are static and kinetic friction coefficients when it takes 1.85 N to start a 2.10 kg body movement and then only 1.50 N to sustain movement?
Wiki User
∙ 15y ago
A body with mass of 2.1 kg has weight of Q = 2.10 * 9.81 = 20.60 N.
To start the movement, the pushing force has to be equal the static friction force:
F = mstatic * Q, where:
F is force,
mstatic is static friction coefficient,
Q is weight.
Solving for mstatic we get:
mstatic = F / Q, or numerically for your data:
mstatic = 1.85 / 20.60 = 0.09
Calculating mkinetic is virtually the same:
F = mkinetic * Q,
mkinetic = F / Q,
mkinetic = 1.50 / 20.60 = 0.07
Wiki User
∙ 15y ago
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