Calcium hydroxide and nitric acid yield calcium nitrate and water. Ca(OH)2 + 2HNO3 --> Ca(NO3)2 + 2H2O
Silver nitrate and lead nitrate do not react, so there would be no precipitate.
Sodium Nitrate is a salt, the product of the reaction of an acid with a base. For instance, Sodium Hydroxide plus Nitric Acid would form the salt Sodium Nitrate and Water. NaOH + HNO3 = NaNO3 + H2O
Equation. NaOH + HNO3 --> NaNO3 + H2O How these products really act in solution. --> Na + + NO3 - + H2O These ions are dissolved in water as any ionic compound would be; Negative, oxygen end of water, surrounding Na + and positive, hydrogen end of water, surrounding NO3 -.
Double Displacement?
Calcium hydroxide and nitric acid yield calcium nitrate and water. Ca(OH)2 + 2HNO3 --> Ca(NO3)2 + 2H2O
The percent of N in sodium nitrate would be 84.6. This is considered a lot of sodium.
Sodium (Na) is a pure substance. Sodium chloride (NaCl) is a compound.
If a solution of NaI is electrolyzed, iodine is formed at the anode and hydrogen gas at the cathode. In the instance if it is the molten liquid of NaI, it would emit sodium from the sodium at the cathode and iodine at the anode.
Silver nitrate and lead nitrate do not react, so there would be no precipitate.
Carbon dioxide wille be evolved in both cases. With hydrochloric acid, sodium chloride is formed; with nitric acid, sodium nitrate is formed
Sodium hydroxide (NaOH) is formed.
Sodium Nitrate is a salt, the product of the reaction of an acid with a base. For instance, Sodium Hydroxide plus Nitric Acid would form the salt Sodium Nitrate and Water. NaOH + HNO3 = NaNO3 + H2O
Hydrogen gas would evolve from the cathode and oxygen gas would evolve from the anode.
Nothing
Double Displacement?
Equation. NaOH + HNO3 --> NaNO3 + H2O How these products really act in solution. --> Na + + NO3 - + H2O These ions are dissolved in water as any ionic compound would be; Negative, oxygen end of water, surrounding Na + and positive, hydrogen end of water, surrounding NO3 -.