The woman could be AA or AO and the man could be BB or BO. The children would all be AB.
if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children
Except type O blood
Assuming the dystonia is hereditary and is a recessive gene which will be called "d" for simplicity, that means the man must be "dd" and the woman is "Dd". This is the only way they could have a child who is "dd" like the father, but not the mother.
heterozygor B man means BO marries with women of O groupthen possibilites of children blood group is 50% BO and 50%OO
50%
if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children
Do a punnet square.I am really bad at them, otherwise I would be more helpful. Got a C in biology.
If all the children are AB, then one parent is AA and the other is BB.
there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.
Except type O blood
What you mean by this question?
25% for blood type O, 50% for blodd type AB, and 25% for A.
Assuming the dystonia is hereditary and is a recessive gene which will be called "d" for simplicity, that means the man must be "dd" and the woman is "Dd". This is the only way they could have a child who is "dd" like the father, but not the mother.
heterozygor B man means BO marries with women of O groupthen possibilites of children blood group is 50% BO and 50%OO
None what so ever.
0 %
The man's genotype is CcFf. The woman's genotype is CcFf. These genotypes only apply if curly hair is dominant to straight hair. Freckles is dominant to no freckles. Also if a man who is heterozygous for both curly hair and freckles who then marries a woman with the same genotype.