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This seeming contradiction occurs on most physics tests. But it's true, and here's why:

Lamp A by itself has power of P=IxE ; 60=IxE ; so I=60/220=0.27 amperes. Thus the lamp has a resistance E=IxR ; R=220/0.27 = 807 ohms.

Lamp B by itself has a power of P=IxE ; so I=100/220 = 0.45 amperes. Thus the lamp has a resistance E=IxR ; R=220/0.45 = 489 ohms.

Since the resistance in series is added up, the total resistance is 807+489 =1296 ohms and the current I= E/R = 220/1296 = 0.17.....

Phew... Since P= IxIxR

For 60W lamp A, P= 0.17 x 0.17 x 807 = 23.3 watts.

For 100W lamp B, P=0.17 x 0.17 x 489 = 14.1 watts.

So, when they are wired in series, the bright one and the dim one appear to be reversed as to their respective "normal rated powers".

Their normal rated powers are only correct when both of them are supplied with their normal rated voltage of 220 volts, i.e. when they are wired in parallel. This makes a lot of sense if you think about it.

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Q: Two lamps A and B are rated 60W 220V and 100W 220V respectively so why does the answer say that when connected in series bulb A is brighter?
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