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The change 232Th90 --> 228Ra88 + 4He2 is an example of the alpha decay of Thorium 232 to Radon 228.

The thorium atom has shed an alpha particle (He-4 nuclei) for a total reduction in atomic weight from 232 to 228 and proton count from 90 to 88.

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Q: This equation is an example of what nuclear decay 232 90 Th to 4 2 He plus 228 88 Ra?
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The following equation is an example of decay 185 79 Au -- 4 2 He plus 181 77 Ir?

alpha


How would you write a nuclear equation for the most likely mode of decay for the unstable nuclide Kr-74?

Krypton-74 will most likely undergo beta decay, and the type of beta decay an observer will encounter will be beta plus decay. A proton in the nucleus will undergo a change and become a neutron, and a positron (e+) and an antineutrino (ve) will emerge from the reaction. The krypton-74 atom will transmute into a bromine-74 atom. The equation will look something like this: 3674Kr => 3574Br + e+ + ve


What is the equation for the beta decay of barium-140?

140Ba decays to B- and 140La plus x-rays and gamma rays.


How do you write a balanced nuclear equation for the positron emission of nitrogen-13?

If oxygen-16 was to undergo positron emission (beta plus decay), a proton in its nucleus would transform into a neutron (mediated by the weak force). The oxygen-16 would become nitrogen-16, and we'd see a positron and a neutrino appear. The equation might look like this: 816O => 716N + e+ + ve It is easy to write a balanced nuclear equation for any nuclide undergoing positron emission. Note the subscript numerals at the beginning of each element. That's the atomic number of that element. The superscript numerals are the atomic mass of the nuclide. When beta plus decay occurs, nuclear transformation takes place. The atomic number of the element goes down by one, and one element becomes another element. The subscripted numerals will reflect that decrease of one, and the atomic mass (the superscripted numerals) will remain the same. Note the last two factors in the equation, as they are the positron and the neutrino, respectively. That's the long and short of the beta plus decay of O-16, as asked. We'll add, however, that oxygen-16 is a stable isotope of oxygen. It does not undergo beta decay, but for the sake of argument, it did here. And with the results shown. By the way, it is oxygen-15 that is the radioactive isotope of oxygen that will undergo beta plus decay. You'll find links below for more information.


What type of decay is 235 92U---4 2 He plus 231 90Th?

Alpha decay

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The following equation is an example of decay 185 79 Au -- 4 2 He plus 181 77 Ir?

alpha


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Beta decay


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Yes. 3a plus 12 plus 6 is an example of an Equation.


When sodium is conrted into a neutron in a beta plus decay?

When sodium is converted into an neutron it will result in the nuclear transmutation.


What kind of nuclear reaction is seen in 146 62 Sm 142 60 Nd plus 4 2 He?

Alpha decay


How would you write a nuclear equation for the most likely mode of decay for the unstable nuclide Kr-74?

Krypton-74 will most likely undergo beta decay, and the type of beta decay an observer will encounter will be beta plus decay. A proton in the nucleus will undergo a change and become a neutron, and a positron (e+) and an antineutrino (ve) will emerge from the reaction. The krypton-74 atom will transmute into a bromine-74 atom. The equation will look something like this: 3674Kr => 3574Br + e+ + ve


What is the equation for the beta decay of barium-140?

140Ba decays to B- and 140La plus x-rays and gamma rays.


4n plus 2 equals 25 is and example of?

An equation


What is missing in the following nuclear equation 99 43 tc plus 99 44 ru?

beta particle


What is missing in the following nuclear equation 247 95Am plus 247 96 Cm?

Beta -apex- :D


201 79 Au -- plus 201 80 Hg what is the missing nuclear equation?

beta particle apex