T = period or time for one revolution in sec
T = (1 / 15.65)(24)(60)(60) = 5520.77 sec
T = [ (2*pi) ] sqrt [ (r ^ 3) / (u) ]
r = R + h
R = radius of earth 6.378E+6 m
h = satellite height in m
u = (G)(M)
G = gravitational constant 6.673E-11
M = mass of earth 5.974E+24 kg
(h + R) ^ 3 = [ (G)(M) ][ [ (T)^2 / (2*pi)^2 ]
(h + 6.378E+6) ^ 3 = [ (3.986E+14) ][ [ (5520.77)^2 / (2*pi)^2 ]
h = 3.731E+5 m
There's just gravity acting as the centripetal force keeping the satellite in its circular orbit. This force is equal to GMEm/r2 = ma = mv2/r.
Satellites orbit the Earth or other bodies due to a careful balance of their velocity and the gravitational attraction of the body. Essentially gravity pulls them down but their velocity moves then out (Newton's Fist Law of Motion) at the same rate. They keep missing the body they orbit.The path is not necessarily circular since the gravity over the Earth varies with the density of the ground below the satellite. They are also satisfied to be in an elliptical orbit (closer at some times than others). The moon is a good example of a satellite in an almost circular elliptical orbit. comets have wildly elliptical orbits.
Velocity of satellite and hence its linear momentum changes continuously due to the change in the direction of motion in a circular orbit. However, angular momentum is conserved as no external torque acts on the satellite.
Straight toward the center of mass of whatever body it's orbiting. If the orbit happens to be circular, then that's the center of the circle.
Not very much, I would say. There is no work being done in this situation so there's no change in kinetic energy. So the satellite's speed remains constant. But we already knew the speed was constant. Perhaps I'm missing something.
Yes.
low-orbit (satellite)
no
A satellite's orbit is just the path it follows around the Earth or some other planet.Satellites' orbits can be elliptical or circular.
for the circular motion of a satellite a centripetal force is requid. these force is supplied by the gravitional force between the earth and satellite this is trueall objects in the satellite is zero ie, the object in a satellite feel weightlessness
circular velocity
There's just gravity acting as the centripetal force keeping the satellite in its circular orbit. This force is equal to GMEm/r2 = ma = mv2/r.
a satellite in orbit; it is moving at constant speed but is accelerating outward in circular acceleration, balanced by gravity acceleration (centripetal force).
-- Gravity (satellite in circular orbit) -- Electrostatic force -- Tension in a string (yo-yo) -- Constraint (marble in a circular track)
In order to appear motionless in the sky, the satellite must be in an orbit that is -- circular -- over the equator -- 22,400 miles above the surface
That's a "geostationary" satellite. It's roughly 22,000 miles above the equator, in a circular orbit.
circular.