1 mg/l = 1ppm
1 g/l = 1000 ppm
NaCl ----------------> Na+ + Cl-
58.5 g NaCl gives 22.989 g Na+
(58.5 / 22.989) = 2.545 g of NaCl is required to give 1 g of Na+
When 2.545 g of NaCl is dissolved in 1 liter water will yield 1000 ppm of Na+ in NaCl solution.
A sodium solution of water cannot be made as sodium reacts violently with water to produce sodium hydroxide.
how will you prepare 0.38M sodium acetate solution
To ensure the stability of the solution
Sodium chloride is a crystalline solid but can be dissolved in water to form a solution.
Preparation of standard solution and standardization of hydrochloric acid Objective : To prepare a standard solution of sodium carbonate and use it to standardize a given solution of dilute hydrochloric acid. Introduction : Anhydrous sodium carbonate is a suitable chemical for preparing a standard solution (as a primary standard). The molarity of the given hydrochloric acid can be found by titrating it against the standard sodium carbonate solution prepared. The equation for the complete neutralization of sodium carbonate with dilute hydrochloric acid is Na2CO3(aq) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l) The end-point is marked by using methyl orange as indicator. Chemicals :solid sodium carbonate, 0.1 M hydrochloric acid
Titrate it with a standard base.
30 gm of sodium hydroxide desolved in 1 litre distilled water.
you can only use the following glassware 5 10 20 25 and 50ml pipette 50 100 200 or 500ml volumetric flasks
52.5g of Na2CO3 in 1 litre water
Sodium chloride may be used as standard (for example to prepare sodium solutions with known concentration) because is a stable compound.
Sodium hydrogen carbonate is used as an indicator of pH or as a test for the concentration of carbon dioxide. For the preparation of the solution see the link below.
Yes, it is an intensive property.