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Is LXXXX greater than XC in Roman numerals giving a reason for your answer?
Wiki User
∙ 12y ago
They both have the same value of 90 because XC is a simplified version of LXXXX.
In the same way that IX is a simplified version of VIIII but they both have the same value of 9
Wiki User
∙ 12y ago
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90 is what in roman numerals?
XC is the usual convention (X =10 subtracted from C = 100). More rarely seen is LXXXX (L=50 and XXXX = 40)
What is the Arabic value of xc?
The Roman numerals XC (100-10) or LXXXX (90) both have the same values of 90 in Arabic numerals (the numbering system that we use today).
Is 99 in Roman numerals IC or XCIX giving a detailed and satisfactory explanation for your answer?
Today we write out 99 in Roman numerals as XCIX because XC = 90 and IX = 9. Therefore it logically follows that XC+IX = XCIX as in the case of Hindu-Arabic numerals. But the Roman numeral system does not contain a zero figure for positional place value purposes. Instead the Romans most probably worked out 99 as IC because:- XC is a simplification of LXXXX IX is a simplification of VIIII So LXXXX+VIIII = LXXXXVIIII and by placing I to both sides of these numerals they can be simplified to IC in fact the Latin word for IC is 'undecentum' which literally means one from a hundred.
In Roman Numerals multiply 38 x 43?
38 x 43 = 1634 which in Roman numerals is MDCXXXIIII Multiplying XXXXIII (43) by XXXVIII (38) in Roman numerals: XXXXIII*XXXVIII = XXX(XXXX+III)+VIII(XXXX+III) Multiplying out the brackets = MCC+LXXXX+CCCXX+XXIIII Total sum of numerals = MDCXXXIIII (1634) By separating the numerals into tens and units makes multiplication a lot easier. In a way this is what we do today when tackling long multiplication.
How would you write 90 has a Roman numeral?
The equivalent of 90 as a Roman numeral is XC or LXXXX
How is 90 expressed in roman numerals?
XC or LXXXX
90 is what in roman numerals?
XC is the usual convention (X =10 subtracted from C = 100). More rarely seen is LXXXX (L=50 and XXXX = 40)
What is the Arabic value of xc?
The Roman numerals XC (100-10) or LXXXX (90) both have the same values of 90 in Arabic numerals (the numbering system that we use today).
Is 99 in Roman numerals IC or XCIX giving a detailed and satisfactory explanation for your answer?
Today we write out 99 in Roman numerals as XCIX because XC = 90 and IX = 9. Therefore it logically follows that XC+IX = XCIX as in the case of Hindu-Arabic numerals. But the Roman numeral system does not contain a zero figure for positional place value purposes. Instead the Romans most probably worked out 99 as IC because:- XC is a simplification of LXXXX IX is a simplification of VIIII So LXXXX+VIIII = LXXXXVIIII and by placing I to both sides of these numerals they can be simplified to IC in fact the Latin word for IC is 'undecentum' which literally means one from a hundred.
In Roman Numerals multiply 38 x 43?
38 x 43 = 1634 which in Roman numerals is MDCXXXIIII Multiplying XXXXIII (43) by XXXVIII (38) in Roman numerals: XXXXIII*XXXVIII = XXX(XXXX+III)+VIII(XXXX+III) Multiplying out the brackets = MCC+LXXXX+CCCXX+XXIIII Total sum of numerals = MDCXXXIIII (1634) By separating the numerals into tens and units makes multiplication a lot easier. In a way this is what we do today when tackling long multiplication.
How would you write 90 has a Roman numeral?
The equivalent of 90 as a Roman numeral is XC or LXXXX
What is the correct notation for 1999 in Roman numerals is it MCMXCIX or IMM giving reasons why?
Under today's guidelines governing the Roman numeral system 1999 converted into Roman numerals is officially MCMXCIX which doesn't seem to add up because:- 1000 = M which is M 900 = CM which is a simplification of DCCCC 90 = XC which is a simplification of LXXXX 9 = IX which is a simplification of VIIII And:- M+CM = CMM which is a simplification of MDCCCC (1900) CMM+XC = XMM which is a simplification of MDCCCCLXXXX (1990) XMM+IX = IMM which is a simplification of MDCCCCLXXXXVIIII (1999) Or:- M+DCCCC = MDCCCC MDCCCC+LXXXX = MDCCCCLXXXX MDCCCCLXXXX+VIIII = MDCCCCLXXXXVIIII Now consider the following:- M+CM+XC+IX = IMM (2000-1) CM+XC+IX+M = IMM XC+IX+M+CM = IMM IX+M+CM+XC = IMM No matter how the above numerals are arranged they will always add up to IMM or MDCCCCLXXXXVIIII in expanded format. Examples of simplification of Roman numerals can be found in the book entitled 'History of Mathematics' volume 2 by David Eugene Smith first published in 1925 and ISBN 0486 204 308. For instance LXXXVIIIIS (89.5) is simplified to SXC (100-10.5) Therefore it follows that for 1999 in Roman numerals IMM is more plausible than MCMXCIX.
What are two different ways of adding together 10 plus 1900 plus 90 but showing all work and final answers entirely in Roman numerals?
Nowadays we would convert 1900 into Roman numerals as MCM but the ancient Romans would have probably worked out the given numbers as follows:-X+CMM+XC = MM => 10+(2000-100)+(100-10) = 2000X+MDCCCC+LXXXX = MM => 10+1900+90 = 2000QED
What are the numbers from 1 to a 1000000 in Roman numerals?
Notwithstanding todays configuration of Roman numerals inasmuch that there is evidence to suggest that the ancient Romans would have written the equivalent of one to a million as follows:-Units: I, II, III, IIII, V, VI, VII, VIII and VIIIITens: X, XX, XXX, XXXX, L, LX, LXX, LXXX and LXXXXHundreds: C, CC, CCC, CCCC, D, DC, DCC, DCCC and DCCCCThousands: (I), (II), (III), (IIII), (V), (VI), (VII), (VIII) and (VIIII)Tens of thousands: (X), (XX), (XXX), (XXXX), (L), (LX), (LXX), (LXXX) and (LXXXX)Hundreds of thousands: (C), (CC), (CCC), (CCCC), (D), (DC), (DCC), (DCCC) and (DCCCC)Million: (M)To select any numerals simply write them out in descending order and then abridge them whenever possible as in the following examples:-900,000 = (DCCCC) = (CM)90,000 = (LXXXX) = (XC)9,000 = (VIIII) = (IX)900 = DCCCC = C(I) or as CM90 = LXXXX = XC9 = VIIII = IX999,999 = (DCCCCLXXXXVIIII)DCCCCLXXXXVIIII = I(M)Check:-(CM)+(XC) = (XM) = 990,000(XM)+(IX) = (IM) = 999,000(IM)+CM = C(M) = 999,900C(M)+XC = X(M) = 999,990X(M)+IX = I(M) = 999,999Note that numerals within brackets indicate multiplication by a thousand and that the practice of placing a bar above a numeral to indicate multiplication by a thousand was introduced during the Middle Ages along with other rules and regulations governing todays Roman numeral system.QED
What is roman numerals of 898?
There are a couple of ways to do it 1. CCM XC VIII That is CCM (800) XC (90) VIII (8). 2. DCCCLXXXXVIII - DCCC (800) + LXXXX (90) + VIII (8) 3. CIIM - CII (102) subtracted from M (1000) If you check the links for accepted usage rules, you will see that #1 is probably the most acceptable
What is the correct procedure when adding together 1000 900 90 12 and 9 using Roman numerals?
To add Roman numerals, follow these steps: Convert each number to its Roman numeral equivalent. 1000 = M, 900 = CM, 90 = XC, 12 = XII, 9 = IX. Add the Roman numerals together: M + CM + XC + XII + IX = (1000 + 900 + 90 + 12 + 9) = 2011. So, the sum of 1000, 900, 90, 12, and 9 in Roman numerals is MMXI.
How would you add up in detail the four numbers of 9 90 900 and 1000 using Roman numerals?
The numbers of 9, 90, 900 and 1000 converted into Roman numerals are IX, XC, CM and M in their simplified format and can be added up in the following manner:- IX+XC = IC (99) IC+CM = IM (999) IM+M = IMM (1999) When added up in their expanded format the result is the same because:- VIIII+LXXXX = LXXXXVIIII = IC when simplified LXXXXVIIII+DCCCC = DCCCCLXXXXVIIII = IM when simplified DCCCCLXXXXVIIII+M = MDCCCCLXXXXVIIII = IMM when simplified The Romans would have used an abacus counting device to calculate the above numerals and probably simplified them in written form as detailed above. Today we don't calculate Roman numerals in the way that the Romans actually did themselves because under today's rules governing the Roman numeral system that were introduced during the Middle Ages the number 1999 is notated as MCMXCIX in Roman numerals. Roman numerals: M=1000, D=500, C=100, L=50, X=10, V+5 and I=1
