Time2 = Distance3 (if time is in years and distance in AU) 112 = distance3 Distance = 4.946 AU The closet planet with that orbit is Jupiter - it has a year (period) of 11.86 earth years and is 778 million km (5.2 AU) from the sun.
At what distance from the Sun would a planet's orbital period be 3 million years?
chocolate pie... but that was 3 years ago...
Yes, the equation p2 = a3, where p is a planet's orbital period in years and a is the planet's average distance from the Sun in AU. This equation allows us to calculate the mass of a distance object if we can observe another object orbiting it and measure the orbiting object's orbital period and distance.
A theoretical planet orbiting our sun every 50 years would have to be about 2,100,000,000 km (2.1 billion km) or around 14 AU from the sun, which is 14 times the earth to sun distance. For comparison, Jupiter is around 9.5 AU and Satrn is around 19 AU.
The computational answer, which would assume identical ellipses for Earth and Saturn, and identical oribital speeds, is a period 10 times that of Earth. The actual "year" for the planet Saturn is 29.7 years.
At what distance from the Sun would a planet's orbital period be 3 million years?
You can figure the approximate distance of a planet if you know its period (and vice-versa) with Kepler's Square-Cube Rule: the cube of a planet's distance is proportional to the square of its period (it's "year"). For example, Jupiter is about 5.2 times as far from the Sun as the Earth is: 5.2 ^3 = 140.608; 140.608 ^ -2 = 11.858. Jupiter takes about 11.858 Earth years to orbit the Sun.
The dwarf planet Sedna is believed to have an orbital period of about 11,400 years. It orbits at a distance between 76 and 937 astronomical units.
The orbital period is 29.447498 years and the rotational period is 0.44401 days. These values are approximate, one can never know the exact figures.
4.2 light years is the distance to the Alpha Centauri Star System.
Saturn.
12 years.
chocolate pie... but that was 3 years ago...
Yes, the equation p2 = a3, where p is a planet's orbital period in years and a is the planet's average distance from the Sun in AU. This equation allows us to calculate the mass of a distance object if we can observe another object orbiting it and measure the orbiting object's orbital period and distance.
30.659 parsecs
A theoretical planet orbiting our sun every 50 years would have to be about 2,100,000,000 km (2.1 billion km) or around 14 AU from the sun, which is 14 times the earth to sun distance. For comparison, Jupiter is around 9.5 AU and Satrn is around 19 AU.
Ceres has a rotation period of 0.3781 days, and an orbital period of 4.6 years.