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Three formulas are used to solve this problem V = Ed, C=(AKE0)/d and Q = CV.

V= Electrical potential (voltage)

E = Electric field (or Electric strength in this case) (3*106 for air

d = distance (plate separation

C = capacitance

A = Surface area (9*10-4 m2)

E0 = 8.85 * 10-12

K = Dielectric constant (roughly 1 for dry Air)

Substitute C and V from the first two formulas into Q = CV.

Q = (AKE0)/d * Ed

the distance cancles and you end up with Q = (AKE0)E.

Substitute in your numbers to find Q

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Q: How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each of the plates is 9.00 cm2?
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