about 30
There are 6.022*10^23 atoms per mole so: 1.1*10^22Ag atoms* 1mole/6.022*10^23atoms = 0.018Ag moles
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
The answer is 3,587 moles.
1 mol Cr/6.02x10^23 atoms x 3.6x10^24 atoms = 5.98 moles
Pieces of atoms? 6.01024 atoms of aluminum (1 mole Al/6.022 X 10^23) = 9.98047 X 10^-24 moles of aluminum ---------------------------------------------------
1 mole of silver contains 6.022 X 10^23 atoms 62 moles of silver contains 3.73 X 10^25 atoms of silver
Quite a few moles of silver if you mean, 4.59 X 10^25 atoms of silver. 4.59 X 10^25 atoms silver (1 mole Ag/6.022 X 10^23) = 76.2 moles of silver ----------------------------
There are 6.022*10^23 atoms per mole so: 1.1*10^22Ag atoms* 1mole/6.022*10^23atoms = 0.018Ag moles
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
The answer is 6,31 moles Ag.
4.55 moles AgNO3 (1 mole Ag/1 mole NO3)(6.022 X 10^23/1 mole Ag) = 2.74 X 10^24 atoms of silver
One mole of atoms is 6.02x1023 atoms, so 10 moles of any substance would contain 6.02x1024 atoms.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
1.50 x 10 to the 23 atoms of fluorine is equal to 0,249 moles.
The answer is 3,587 moles.
Divide 1.8*10^20 (unit: number) particles by 6.02*10^23 (unit: number per mole), Avogadro's number) and you'll get3.0*10^(-4) moles of those particles(In your case particles are atoms, but this is also valid for ANY kind of particles)
In a mole there is 6.022 x 1023 atoms. In two moles there are twice that amount.