19.2 moles
The answer depends on the quantity of XeF6
3.2 mol XeF_7 * 7mol F/1mol XeF_7 = 22.4 mol F Easy as pie.
The answer depends on the quantity of Xenon.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
48 6 for sulfur 7 x6=42 for hexafluoride
The answer depends on the quantity of XeF6
3.2 mol XeF_7 * 7mol F/1mol XeF_7 = 22.4 mol F Easy as pie.
The answer depends on the quantity of Xenon.
1,8 grams of fluorine is equivalent to 0,0947 moles.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
48 6 for sulfur 7 x6=42 for hexafluoride
(63.29oz.)
Approx 0.46 moles.
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
.298 Moles
5.66 X 1023 atoms of xenon (1 mole Xe/6.022 X 1023) = 0.940 moles of xenon ------------------------------
0.94 moles.