1.305 mol CO
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
The answer is 7,829.10 ex.23 atoms.
The equivalence is 1992 moles.
350 g sample of CO contain 12,49 moles.
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
The answer is 7,829.10 ex.23 atoms.
The equivalence is 1992 moles.
2,55 moles of the compound CO have 71,4 grams.
350 g sample of CO contain 12,49 moles.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
In order to find number of molecules from moles, you must multiply moles by avagadro's number, which is 6.02*10^23.
Carbon Monoxide-CO. 1carbon atom.
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
If you have 1.4 mol of carbon before the reaction you have 1,4 mol of carbon after the reaction. If you make carbon monoxide, CO, then you need 1.4 mol of CO after the reactiion. If you make carbon dioxide, CO2, you need 1.4 mol of C2O, because you have one carbon in each molecule.