There are 0.003659 N2O moles. So there are o.007318 moles of N.
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
There is no nitrogen in water.
35.0 moles nitrogen (1 mole N/14.01 grams) = 2.50 moles nitrogen ----------------------------
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
The number of moles is 3,316 (for atomic nitrogen).
0,189 g of N2O equal 0,0043 mol.
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
The answer is 1,52 moles.
Molar mass: 44.013 g/mole 81.0/44.013=1.84 mole N2O Moles of N 1 mole N2O contains 2 atoms N 1.84 mole N2O contain 1.84*2=3.68 mole N atoms
One molecule of N2O N 2 O contains one atom of oxygen.
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
When using the preferred resonance structure [ N (triple bond) N (single bond) O ] the bond order of N-O in N2O is 1.
The answer is 0,0043 moles of N2.
1 mole N = 14.0067g N 78.56g N x 1mol N/14.0067g N = 5.609 moles N
This is a thermal decomposition reaction.