There are 0.13 moles in 20 grams of magnesium nitrate.
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
Stoichiometry! Set up the equation: C + O2 --> CO2.First, run it through for 20g of C: 12g/1mol=20g/x; x=1.67 mol, which in the equation, is also your moles for CO2 because everything's in a 1:1 ratio.Now, run it through for 50g of O2: 32g/1mol=50g/x; x=1.56 mol, which is also your moles for CO2 for the same reason as above.1.56 is less than 1.67, so 1.56 moles CO2 is the true answer (1.67 is an impossible scenario). The O2 is the limiting reactant (the carbon is the excess.) The 1.56 moles of CO2 produced is also equal to 34.94 liters (at STP) or 68.64 grams.
Density is mass per unit volume. If 10 cm3 weighs 20g, the density is 2 g/cc.
20g = 0.705 oz.
You cannot directly associate weight and volume. You firstly need to know the shape and other dimensions in order to find the volume. Then you need to apply the density of the material, i.e. what it weighs per volume.
Formation of magnesium chloride: Mg + 2 HCl -> MgCl2 + H2
The molar mass of sulfur dioxide is 64,066 g.
Moles = Mass/Molar Mass.Using this equation, we can take 25/(1.0 + 19) and find that it is equal to 1.25 moles.Keep in mind that very few significant figures were used for this example (2), and that if accuracy is to be expected, as many as possible should be used.
Masses: Mg= 24, S= 32, O= 16 Magnesium = 24g Magnesium sulphate = (24+32)+(16x4) = 120g. Therefor we know: 24g of Mg ----> makes 120g of MgSO4. To get to 4g from 24g, you devide by 6. (24 devided by 6 = 4g) And to find what it would make, you devide 120 by 6 too. Which = 20g. 4g of Mg ----> 20g of MgSO4.
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
Hi, I tried this one but got a weird answer, anyway...... pH = -Log[H+] (H+ ion conc. in mol/L) and there's one H+ per molecule of methadone HCl. At 2% w/v there is 2g in 100ml and therefore 20g in 1L. how many moles of MethadoneHCL in 20g? Calc using MW which is 346.5. You have ( 20/346.5 moles of the drug and hence 20/346.5 moles of H+ ions) a 1:1 ratio. That works out as 0.0577 moles of H+ and using formula a pH of about 1.24.
20g
9,000 and 20.
20,000mg = 20g
That is approximately 5.835 teaspoons.
20g = 20000mg.
20g