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divide the mass by molar mass. Molar mass of NH3 is 17. answer is 0.044mol
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∙ 8y ago
Wiki User
∙ 8y agoMolar mass of ammonia is 17 g. Hence 0.75 g of ammonia will contain 0.044 moles of ammonia.
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How many moles are in 12 x 10.3 grams of ammonia NH3?
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
How many moles are in 1.2 X 10.3 grams of ammonia NH2?
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
How many molecules are in .75 g of ammonia?
This is a chemical calculation. there are 0.04166 moles in it.
How many molecules (not moles) of NH3 are produced from 5.95104 g of H2?
The number of ammonia molecules is 59 720.10e23.
What is the number of moles in 2.30 L of NH3 gas at STP?
2.3L / 22.4 liters per mole = approx. 0.1 moles.
How many moles are in 12 x 10.3 grams of ammonia NH3?
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
How many moles s are present in 1 g of ammonia?
1 g of ammonia (NH3) is equal to 0,059 mol.
How many moles are in 1.2 X 10.3 grams of ammonia NH2?
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
How many molecules are in .75 g of ammonia?
This is a chemical calculation. there are 0.04166 moles in it.
How many moles of ammonia is 170000g?
Ammonia = NH3Molecular mass = 16.0Formula of grams to moles: grams / molecular mass = moles170,000 g / (16.0) = 10,600 moles NH3Note that the answer is with three significant digits
How many grams of NH3 can be produced from 2.79 moles of N2?
The mass of ammonia will be 95,03 g.
How many moles are present in 1 g of ammonia?
5.8 x 10-2 mol
What would be the Mass of 3 moles of ammonia and calculate the number of ammonia molecules?
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
300 g of ammonia react with 36 moles of sulfuric acid to produce ammonia sulfate how many moles of excess sulfuric acid are left over after the reaction is complete?
26.9 - 27.4
How many moles of NH3 can be produced by the reaction of 2.00 g of N2 with 3.00 g H2 Reaction N2(g) plus 3 H2(g) 2 NH3(g)?
2 mol H2 x 2 mol H2O/2 mol H2 x 18 g H2O/1 mol H2O = 36 g H2O
How many molecules (not moles) of NH3 are produced from 5.95104 g of H2?
The number of ammonia molecules is 59 720.10e23.
