35. Salt is sodium.
1/4 teaspoon salt = 600 mg sodium 1/2 teaspoon salt = 1,200 mg sodium 3/4 teaspoon salt = 1,800 mg sodium 1 teaspoon salt = 2,300 mg sodium
Unlike many other vegetables, celery is relatively high in salt (sodium). The average stalk of celery contains about 35 mg of sodium. Those on a diet of 1000 mg or less of sodium may wish to avoid celery and choose a lower-sodium vegetable.
One teaspoon (5 milliliters) of table salt has 2,325 mg of sodium
.035 g
2608 mg of salt is 1500 mg of sodium i.e. half a teaspoon
1 mmol sodium = 23 mg sodium chloride 80 mmol sodium chloride = 80 x 23= 1840 mg sodium chloride
500 mg of sodium is equivalent to 0.5 gram of sodium, which in turn is equivalent to around 1.27 gram of common table salt (sodium chloride).
The premium Asian salad contain 35 mg sodium; for other salads see the link below.
One teaspoon of salt contains 2000 mg of sodium, so 380 mg of sodium would be about 1/5 a teaspoon of salt.Read more: My_soup_label_says_380_grams_of_sodium_-_how_many_teaspoons_of_salt_would_that_equal
Hold on here, I need to do some heavy calculation ... okay, done. One tablespoon of table salt contains 1.0 tablespoons of sodium chloride. Since the atomic weight of sodium chloride is 58.5, 1 meq of salt is 58.5 mg. Since one tablespoon = 14.8 ml and salt weights 1.02 g/ml, one tablespoon of salt weighs 15.2 g or 15,200 mg. So one tablespoon of salt = 15,200 / 58.5 = 260 mEQ.
this question is not hard to answer, but it does require that one make some assumptions. The simplest answer assumes that the 20% salt solution refers to per cent by mass. Thus: a 20% salt solution is one which contains 20 mg salt for every 100 mg solution where the solution consists of a mixture of 20 mg salt plus 80 mg water. A 35% salt solution would contain 35 mg salt for every 65 mg water. Now, assuming that all the water in 18 mg of a 20% salt solution remains in the final solution we see that 18 mg salt solution x 20 mg salt/100 mg salt solution gives 3.6 mg of salt; thus, there are 18 mg total solution - 3.6 mg salt = 14.4 mg water. So the final salt solution must be one that contains 14.4 mg water and enough salt to make it 35% salt by mass. Mathematically, this is written as Z mg salt/(Z mg + 14.4 mg water) = 35/100 This gives Z = 0.35*(Z + 14.4) or Z = 0.35*Z + 0.35*14.4 which is same as Z = 0.35*Z + 5.04 and 0.65*Z = 5.04 so Z = 5.04/0.65 = 7.75 mg total salt needed. We started with 3.6 mg salt, so we must add 7.75 -3.6 = 4.15 mg salt Check: 7.75 mg salt/(7.75 mg salt + 14.4 mg water) = 0.35 or 35% There you go! --assuming that much salt dissolves that amount of water!
1.6 g