Pi x Radius Squared x length in inches / 231 ci in a gallon 3.14 x 2 squared x 50 feet x 12 inches = 7,536/231 = 32.6 Gallons
9 gallons
A standard fire hose is 50 feet long. A hose this length with a 2-inch radius grants about 4.36 cubic feet. This volume holds 32 gallons of water.
12.5
50 feet of 2.5-inch diameter hose has a volume of: 1.7 cubic feet (12.72 liquid gallons)
There need not be any water at all in the hose! The capacity of the hose is 3.41 cubic feet.
A 100-foot hose with an inside diameter of five inches can hold 102 US gallons of water.
NFPA 1901, Standard for Automotive Fire Apparatus - Requires pumpers to carry: * 15 feet of large soft sleeve hose or 20 feet of hard suction hose * 1200 feet of 2 ½ inch or larger supply hose * 400 feet of 1 ½ , 1 ¾, or 2 inch attack hose
100 feet by 100 feet by one inch equates to 6,233.76 gallons of water.
179.53 gallons
Do you mean a fixed length of 5 inch pipe or are you asking to the amount of laminar flow through a 5 inch pipe? There is not enough info here to answer. Need length of pipe and what you are asking.
If "6 inch" is the inside diameter of the hose, thenVolume = (pi) (radius)2 (length) = (pi) (3)2 (1,200) = 33,929.2 cubic inches = 146.88 gallons (rounded)
1.03 gallons
One gallon is 231 cubic inches. Assuming cyllindrical shape of hose, it contains 100 * 12 * 5 * PI * 0.25 * 52 cubin inches, which is 11780 cubic inches = 51 gallons.