How many atoms of calcium are present in 58.2 g of calcium?

Answer 1

One mole of anything, no matter what the element is, is Avogadro's number, which is 6.02 * 10^23 atoms.

One mole of Calcium is equal to it's atomic weight in grams :

1 mole Ca = 40.08 g = 6.02 * 10^23 atoms

There is a 1000mg in a gram. 1000mg * 40.08g =

=40,080mg of Ca per mole

If you have 8.6mg of Ca that is 8.6mg / 40,080mg = .00021457 of a mole of calcium

so just multiply that by Avogadro's number to give you number of atoms:

.00021457 * 6.02 * 10^23 atoms = 1.292 * 10^20 atoms of Ca

Answer 2

8 grams.

Atomic Mass of Calcium = 40 amu

1 Gram atomic mass of Calcium = 40 gram

1 Gram atoms of Ca = 40 gram

8 Gram atom o Ca = 40 x 8 = 320 grams

You will find plenty of such derivations on www.examville.com. I go to the site for all my chemistry problems.

Answer 3

8.74 * 10^23 First you need to find how much moles of calcium that is, since 1 mole of calcuim is 40.08. You need to divde 58.2 by how much is one mole ( 58.2/40.08=1.452 moles). Once you know how many moles there are you have to , find how much particles there are. ( 6.o221*10^23*1.45=8.75*10^23)

Answer 4

38.3 grams calcium (1 mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca)

= 5.75 X 10^23 atoms of calcium

Answer 5

1.2044 x 1024

Answer 6

the anser is 10000mall