Look at the motor nameplate and it shoud have the amp draw on it. If the nameplate is missing, then the amp draw depends on what type of motor it is.
The basic calculation to get you in the ball park would be as follows:
1 HP = 0.75 KW
7.5 HP = 5.63 KW
Assume the efficiency of the motor is 80%, then the power supplied will need to be 5.63/0.8 = 7.04 KW
amp draw = 7040/220 = 32 amps
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For calculation purposes the electrical code book states that a 7.5 HP motor draws 40 amps.
read the name plate on the motor
50 Amps Single Phase 20 Amps Three Phase
Then you are trying to get more HP out of the motor that it can supply. Back off on the load that the motor is driving or put a bigger motor onto the load.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
depends on the number of cans and the specific gravity of the electrolyte
40 amps
8,33 Amps
X / 415 = 80 / 220 = 151 amps
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
A 1-HP motor is reckoned to draw 7 amps at 240 v single-phase. The same power of motor would draw 3.5 amps at 480 v single-phase, but a 480 v supply could most likely be a three-phase suppy, and the current in that case would be reckoned as 2 amps.
To answer this question the voltage of the heater must be given. I = W/E.
It means 225 amps on each phase.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
read the name plate on the motor
50 Amps Single Phase 20 Amps Three Phase
106 amps
24 amps. This could be three 11.54 resistors connected in star, or three 34.6 ohm resistors connected in delta.