0,16 mg NaCl is equivalent to 2,7.10-5 mol.
15 mg NaCl is equivalent to 2,567.10-4 mol.
in Nacl there is 1 formula unit
150 g NaCl is equivalent to 2,567 mol.
7,8 g of NaCl contain 0,814.10e23 formula units.
The answer is 4,328.1023formula units (not molecules).
1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3.6g NaCl x 1mol NaCl/58.443g NaCl x 6.022 x 1023 formula units NaCl/mol NaCl = 3.7 x 1022 formula units NaCl
1 mole NaCl = 6.022 x 1023 formula units NaCl 2.9 x 1021 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl = 0.0048 mole NaCl
How many grams of NaCl are present in 8.39x10^22 formula units of NaCl?
The term molecule is not adequate for an ionic compound; correct is formula unit.60 g NaCl contain the equivalent of 1,026 formula units.
The number of formula units of NaCl is 11335.10e17.
1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3 x 1025 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl x 58.443g NaCl/mol NaCl = 2911g NaCl = 3000g NaCl (rounded to 1 significant figure)
4.5 moles NaCl = 4.5000000000001 formula units NaCl *******************2nd Opinion************* 4.5 moles of NaCl would contain 4.5 x (6.02 x 1023) formula units. = 2.7 x 1024 formula units
0,665 moles NaCl is equivalent to 38,86 g.
Use stoichiometry. 3.5g-> moles 22.99+16+1.0079=39.99 Now 3.5/39.99 = .088 moles of NaOH Now you can use avagadros number 6.022x10^23 .088 moles -> formula units .088/6.022x10^23 You should end up with 1.46x10-25 formula units. Yeah, I know, Chem sucks huh?
The formula unit of NaCl (sodium chloride) contain 2 atoms.