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The intensity increases by a factor of 4

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Portia Baranowski

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Q: How does the intensity of a sound wave change if the distance from the source increases by a factor of 2?
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How does the intensity of a sound wave change if the distance from the source is reduced by a factor of 4?

- 6 dB is incorrect. It will decrease by 12 dB.


An increase of 20 dB increases the sound intensity by a factor of?

A factor of 100. Every 10 dB, the intensity increases by a factor of 10.A factor of 100. Every 10 dB, the intensity increases by a factor of 10.A factor of 100. Every 10 dB, the intensity increases by a factor of 10.A factor of 100. Every 10 dB, the intensity increases by a factor of 10.


How does gravitational force change if distance decreased by half?

The gravitational force then increases by a factor of 4 .


How many times louder is an 80 dB sound compared to a 40 dB sound?

1000 times louder. Every 10 decibel, the intensity increases by a factor of 10.1000 times louder. Every 10 decibel, the intensity increases by a factor of 10.1000 times louder. Every 10 decibel, the intensity increases by a factor of 10.1000 times louder. Every 10 decibel, the intensity increases by a factor of 10.


By what factor will the noise intensity change when sound levels increases by 8 db?

That answer is not easy, but ccroll down to related links and look at "Sound level dependence and the corresponding factors". ten


Tripling the distance from a constant intensity point will cause the illumination to?

Decrease by a factor of 9


How does intensity vary with distance from the source?

It's an inverse-square law - for instance, double the distance, and the intensity will be reduced by a factor 1/4.This assumes that there is nothing absorbing the light (for instance, fog); if there is, the intensity in the above example will of course be even less than 1/4 the original intensity.


If the distance between the spheres is cut in half what is the force between the masses?

The force increases by a factor of 4. If we're talking about gravity, the gravitational force is a function of the masses and the square of the distance between them. As distance decreased by a factor of 2 (since it was cut in half), then the force increases by a factor of 2 squared, and that's 4. Gravitational force increases by a factor of 4 when distance between two gravimetrically attracted objects is decreased by a factor of 2 (cut in half).


How do you double decibels?

When doubling the field quantity factor by 2 the level increases by 6 dB. When doubling the energy quantity factor by 2 the level increases by 3 dB. When doubling the sound pressure value by 2 the level increases by 6 dB. When doubling the sound intensity value by 2 the level increases by 3 dB. The decibel (dB) is a logarithmic unit that indicates the ratio of a physical quantity relative to a specified or implied reference level. You usually don't double decibels - you double the factor (ratio). Look at the link "Subjectively perceived loudness (volume), objectively measured sound pressure (voltage), and theoretically calculated sound intensity (acoustic power)".


By what factor will the sound of a source change the intensity of the waves if the distance is tripled from the sound source?

For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.


Gases kept at constant temperature if its temperature is change from 50 celsius to 100 celsius by what factor does the factor change?

The temperature factor increases to 1.1547, approx.


A sound that is perceived as twice as loud requires how much intensity?

Scroll down to related links and look at "Sound level change and the change of the respective factor of volume / loudness, sound pressure / sound intensity".