0
How do you find time of flight from initial velocity and an angle at which an object is thrown?
Wiki User
∙ 14y ago
If you're willing to ignore the effect of air resistance, then the answer is as follows: The object's horizontal velocity remains constant (at least until it eventually hits the ground). The vertical component of the object's initial velocity ... call it V(i) ... is the (total initial velocity) multipled by the (sine of the initial angle above the horizontal). Beginning at the time of the toss, the magnitude of the vertical component of velocity is V = V(i) - 1/2gT2. T = number of seconds after the toss g = acceleration of gravity = approx 32 ft/sec2 or 9.8 m/sec2
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoIf you have the initial velocity of an object and the angle at which it was thrown, you can calculate the time of flight.
First, you must break the velocity into its x and y components. The x component can be found by using the equation:
Vcos(theta) = x component of the velocity
(V is the velocity and theta represents the angle at which the object was thrown.)
The y component can be found with:
Vsin(theta) = y component of the velocity
In this problem, we only need to worry about the y component. Once you calculate it, you can plug it into this equation:
t = g/v
(since this is in the y direction, the acceleration will be g, gravity or 9.8 m/s^2)
This will give you the time it takes the object to reach it's peak height. It will take the same amount of time to then fall to the ground, so the final answer will be 2t.
Add your answer:
Earn +20 pts
An object is thrown vertically upwards from the top of a tower of height 39.2 meters reach the ground in 4 secons Find the velocity with which it is thrown upwards?
Using the equation: x=vot+(1/2)at2 x: -39.2m (though the object is thrown upwards, its total displacement is just the amount it fell from the tower). vo: initial velocity t: 4 s a: -9.8m/s2 (assuming we're on the earth's surface) -39.2=vo(4 s)+(1/2) (-9.8m/s2)(4 s)2 ((78.4 m - 39.2 m)/ 4 s) = v0 So the initial velocity is 9.8 m/s.
If an object is thrown up in the air how does its gravitational potential energy change?
If the objects only source of thrust is the hand, it does not accelerate, it decelerates due to friction and resistance.Answer:The object accelerates as it is propelled upward and is still in contact with the hand. This cannot be determined without data on the velocity at which it leaves the hand. The formula used is:a=vf - vi / twhere a is accelerationvf is final velocityvi is initial velocityand t is time takenOnce free it accelerates negatively at the gravitational constant "-g" (-32 ft/sec2). Upon reaching the apex of its trajectory it accelerates downward at g=32 ft/sec2 until it strikes the ground. If the object is thrown in an atmosphere the apex of the trajectory is reduced by drag and the downward velocity reaches a maximum at the object's terminal velocity.
A body can escape the gravitational pull of the earth if it is thrown up with a velocity of?
An object would need to start at about 25 miles per second in order to escape Earth's gravity.
Can an object be moving when its acceleration is zero?
Acceleration, which is the change of velocity over the change in time, will equal zero when there is no change in velocity. This can occur when an object is stationary or when an object is traveling at a constant velocity.
An object of a mass of 2.5 kg is thrown upwards with an initial speed of 39 ms How fast is the object traveling just before it hits the ground Assume that there is no air resistance?
Assumptions: 1) You throw it straight up. No angle, nothing. 2) Answers.com removed your punctuation, thus you meant initial speed of 39 m/s 3) No air resistance 4) Your "throw" begins at the ground (meaning you're not counting the height of the person) Answer = 39 m/s Reasoning: With nothing but the acceleration of gravity to slow it, it will slow to a stop, then accelerate and return along the same path. With no resistance, it will accelerate to the same velocity as its initial velocity by the time it reaches the point of origin. Fun Fact: Feel free to try this. I recommend using a hackey-sack and laying on your back while you throw upward.
What is the best way to analyze an object thrown into the air?
whenever an object is thrown in the air we must know the initial velocity with which the object has been thrown.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
Is acceleration greater when the object is thrown vertically or horizontally?
Acceleration is dependent on the initial velocity of how fast the object is leaving the projectile. The vertical acceleration is greater when the object is falling than when the object reaches the peak in height. However, if the object is thrown horizontally and there is no parabola in its shape then there is not as great of an acceleration.
Initial velocity of a softball thrown at 30 mph?
30 mph!
Does uniform negative acceleration properly characterize the motion of a heavy object thrown violently downward from a tall building?
The largest variation from two objects moving downward either 'dropped' or 'thrown' thereby allowing earth's natural gravity to increase until an object approaches and/or reaches maximum velocity. The difference in the two examples, 'dropped' or 'thrown' objects merely illustrates that the "thrown" object will reach maximum velocity quicker than the 'dropped' object.
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
A baseball was thrown from 1 m hill Assume that the ball had an initial velocity of 70 kmh 19.44 ms at 40 degreesWhat was the initial velocity on x direction?
initial velocity on xx=vi*cos(angle) 53.62 kmh 14.89 ms
If a small marble is dropped straight downward what is the initial velocity of the marble?
The initial velocity is zero. In most basic physics problems like this one the initial velocity will be zero as a rule of thumb: the initial velocity is always zero, unless otherwise stated, or this is what you are solving for Cases where the initial velocity is not zero examples a cannon ball is shot out of a cannon at 50 mph a ball is thrown from at a speed of 15 mph etc
What moves faster a ball thrown down or a ball falling down?
A ball thrown down. The thrown ball will have a greater initial velocity and since they experience the same force of gravity, it will always be faster (until they both reach terminal velocity).
Does weight affect how far an object travels?
yes it does, however, the velocity at which the object is thrown also is a factor to consider.
When will a stone return to the groun if it is thrown upward with an initial velocity of 16ms?
After just over three and a quarter seconds.
