foreach char in string
push on to stack
create new string
foreach char in string
pop off and add to end of new string
if new string equals old string
palindrome
else not palindrome
//when you pop off the stack, the characters come off in reverse order, thus you have reversed the original string
You can use a stack to determine if a string is palindromic by pushing each character onto the stack, and then reading the string again while popping each saved character from the stack. If they match, then the string is palindromic.
/** C Program to Check String is Palindrome using Stack.*/#include #include void push(char);char pop();char stack[100];int top = -1;void main(){char str[100];int i, count = 0, len;printf("Enter string to check it is palindrome or not : ");scanf("%s", str);len = strlen(str);for (i = 0; i < len; i++){push(str[i]);}for (i = 0; i < len; i++){if (str[i] == pop())count++;}if (count == len)printf("%s is a Palindrome string\n", str);elseprintf("%s is not a palindrome string\n", str);}/* Function to push character into stack */void push(char c){stack[++top] = c;}/* Function to pop the top character from stack */char pop(){return(stack[top--]);}
what ever you assume
/*To check whether a string is palindrome*/includeincludevoid main () { int i,j,f=0; char a[10]; clrscr (); gets(a); for (i=0;a[i]!='\0';i++) { } i--; for (j=0;a[j]!='\0';j++,i--) { if (a[i]!=a[j]) f=1; } if (f==0) printf("string is palindrome"); else printf("string is not palindrome"); getch (); }
import java.util.Scanner; public class Palindrome{ public static void main(String[] args){ String front; String back =""; char[] failure; String backwards; Scanner input=new Scanner(System.in); System.out.print("Enter a word: "); front=input.next(); front=front.replaceAll(" ", ""); failure=front.toCharArray(); for (int i=0; i<failure.length; i++){ back=failure[i] + back; } if (front.equals(back)){ System.out.print("That word is a palindrome"); }else System.out.print("That word is not a palindrome"); }}
palindrome in every language means same. it means on reversing a number or string, if we get the same number or string as the case may be ,then the number or string is called palindrome. eg: 1221,111,252 or LIRIL,MADAM etc .
Reverse the string and compare it to the original. If they match, then it is a palindrome.
/** C Program to Check String is Palindrome using Stack.*/#include #include void push(char);char pop();char stack[100];int top = -1;void main(){char str[100];int i, count = 0, len;printf("Enter string to check it is palindrome or not : ");scanf("%s", str);len = strlen(str);for (i = 0; i < len; i++){push(str[i]);}for (i = 0; i < len; i++){if (str[i] == pop())count++;}if (count == len)printf("%s is a Palindrome string\n", str);elseprintf("%s is not a palindrome string\n", str);}/* Function to push character into stack */void push(char c){stack[++top] = c;}/* Function to pop the top character from stack */char pop(){return(stack[top--]);}
poooda
To check if a string is a palindrome, point to each end of the string and work inwards towards the middle. If the characters pointed at differ, the string is not a palindrome. When the pointers meet or cross each other, the string is a palindrome. Note that the string cannot contain whitespace or punctuation and comparisons must not be case-sensitive.
A string palindrome is some words that put together form a sentence. An example is "A man, a plan, a canal - Panama".
A string palindrome is some words that put together form a sentence. An example is "A man, a plan, a canal - Panama".
what ever you assume
/*To check whether a string is palindrome*/includeincludevoid main () { int i,j,f=0; char a[10]; clrscr (); gets(a); for (i=0;a[i]!='\0';i++) { } i--; for (j=0;a[j]!='\0';j++,i--) { if (a[i]!=a[j]) f=1; } if (f==0) printf("string is palindrome"); else printf("string is not palindrome"); getch (); }
You could use a function like this:function isPalindrome($string) {$string = strtolower($string);return (strrev($string) == $string) ? true : false;}and then to check a palindrome call an if statement like so:if(isPalindrome($test)) {echo $test.' is a palindrome';}else {echo $test.' is not a palindrome';}
import java.util.Scanner; public class Palindrome{ public static void main(String[] args){ String front; String back =""; char[] failure; String backwards; Scanner input=new Scanner(System.in); System.out.print("Enter a word: "); front=input.next(); front=front.replaceAll(" ", ""); failure=front.toCharArray(); for (int i=0; i<failure.length; i++){ back=failure[i] + back; } if (front.equals(back)){ System.out.print("That word is a palindrome"); }else System.out.print("That word is not a palindrome"); }}
If you mean the number 1,111 or simply 1111, this is a palindrome. A palindrome is a string or number that is spelled or written the same way forward and backward.
palindrome in every language means same. it means on reversing a number or string, if we get the same number or string as the case may be ,then the number or string is called palindrome. eg: 1221,111,252 or LIRIL,MADAM etc .