when velocity of a car is increasing then velocity and acceleration are parallel to each other.
Explain circumstances, in which the velocity acceleration of a body is parallel?
the acceleration of the car is increasind.Then the v and a are parallel to each other.
Yes, you can. Zero acceleration simply means there is no CHANGE in velocity. It doesn't mean there is no velocity.
Of course. A car with brakes applied and slowing down has forward velocity and rearward acceleration.
It doesn't "affect" it. Acceleration is DEFINED as (delta v) / (delta t), or change in velocity divided by the time elapsed; so whenever you have a delta-v, you'll have an acceleration (the amount of which also depends on the time elapsed).
Acceleration is the change of velocity, with direction. Therefore slowing down is a change in veolcity, so is considered to be acceleration (just negative acceleration).
When an object is moving with different velocity with respect to time then the object is in acceleration or decceleration mode. If the rate of change of velocity is positive then it is said to be accelerated, if its negative it is said to be deaccelerated.
Centrifugal governors respond to angular velocity. Inertia governors respond to angular acceleration.
Do you agree with the statement, "An object with a zero velocity can have an acceleration greater than zero."? Explain your answer.
Acceleration is change in velocity over time. a = vf - vi/Δt, where a is acceleration, vf is final velocity, vi is initial velocity, and Δt is the time interval. For example, a car accelerates from rest to 15m/s in 5.9s. What its acceleration? vi = 0m/s, vf = 27m/s, Δt = 5.9s, a = ? a = 27m/s - 0m/s/5.9s = 4.6m/s/s = 4.6m/s2
Acceleration = 0 because the car is moving at a STEADY velocity. It is neither speeding up, nor slowing down.
When a body moves with uniform, its acceleration is is constant if v(m/s) t(s) a(m/s2) 4 1 0 8 2 4 12 3 4 16 4 4 (8-4/1)=4 12-8/1=4 hence acceleration is constant.