Please name this analysis for a possible answer.
The concentration is 12,8 g/L NaOH.
The concentration of NaOH is 99,32 g/L.
HCl + NaOH ---> NaCl + H2O(53.1 ml)(0.300 M) = (15.0 ml)(x M)x = 1.06 M
-10.6c
How to work it out - Calculate the concentration of the solution in terms of molarity. Calculate the hydrogen ion concentration from the fact that multiplying the hydrogen and hydroxide concentrations (in mols per litre) will always give 1x10-14. Take the -log10 of the hydrogen ion concentration.
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
It allows the concentration of the NaOH to be known.
The concentration is 12,8 g/L NaOH.
It should take just exactly twice the volume to reach the balance point.
The concentration of this solution (in NaOH) is 40 g/L.
fap
it depends on the concentration of NaOH, pepsin, buffer used, ... that cannot be answered in that way...
The concentration of NaOH is 99,32 g/L.
0.86
increase
Increasing the concentration of NaOH the density also increase.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.