positive
negative
On Earth it's 9.8 m/s^2. Gravitational acceleration is constant.
The impact velocity of a rock thrown horizontal from a cliff depends on two things, the initial speed of the rock (vi) and the height of the cliff (h). The final velocity (impact velocity) is represented by vfFor this formula, air resistance is neglected, and acceleration due to gravity is assumed to be 9.8 m/s2. The acceleration is positive here because down is being treated as the positive direction. You will get the same result if you use negative 9.8 m/s2 and make the height negative. sqr() means square root.vf = sqr(19.6h + vi2)For example if the rock was thrown off a 3 meter high cliff at 20 m/s, the impact velocity would be sqr(19.6 x 3 + 202), which would be sqr(58.8 + 202), which would be 21.42 m/s.The angle relative to the ground is the inverse tangent of sqr(19.6h)/viwhich in this case is tan-1( sqr(19.6 x 3)/20), which is tan-1(7.67/20) which is 21.0 degrees.
It means there is no net force acting on it. A plane in the air has no acceleration, but it does have forces acting on it. Lift pushes it up Gravity pushes it down Air resistance opposes its movement Thrust provides movement When all these forces are equal the plane will move at a constant velocity. If one of these forces becomes greater the NET force on the plane will no longer be 0 and there will be an acceleration or deceleration. Hope that helps. Another example would be space as there are no opposing forces, if in space once a speed was that speed would be constant until you 1.) decelerated with a force in the opposite direction 2.) accelerated the speed past your current velocity in your current direction 3.) Get caught by some planets gravity and crash to you death (but then this question is the least of your problems)
Since the question is asking you to compare the acceleration after the pins have been released, the only force acting on each pin is gravity. Therefore, the acceleration on both pins is the acceleration due to gravity, or 9.8 m/s2 towards the earth. Even though one of the pins is being thrown up, once released, the acceleration is still 9.8 m/s2 towards the earth.Each pin has the same acceleration.
Answer:Yes, but only instantaneously.Consider a thrown ball moving directly upward. At the highest point of its trajectory, the instanataneous velocity (the velocity at that precise instant) is zero even while the acceleration due to gravity remains non zero.
If the object is thrown upwards, the vertical acceleration is negative and the horizontal acceleration is zero.
well the difference between positive and negative velocity would have to be that if your motion speeds up than you have a positive and when or if your motion slows down then you would have a negative accelerarion!!!!
When we throw the object upwards we consider that upward direction as positive. Therefore, the velocity in that direction is positive but the acceleration due to gravity is in the opposite direction and so it is considered negative. But when the ball comes down again after reaching a certain height the velocity is in opposite direction to the earlier one and so the velocity now is negative as a result the acceleration is again negative.
488 inches
A baseball can
Yes. On the way up, negative acceleration is taking place because the ball is moving up and gravity is acting in the opposite direction. On the way back down, acceleration is positive, and the object starts at rest.
A force is when there is an automatic out at the base if the ball is thrown there
After being released, a ball thrown straight down from a bridge would have an acceleration of
30 mph!
PIT is pitches thrown or pitch count.
No, the acceleration at the highest point is never 0.
The gravitational force on an object near the surface of the earth, and the object's acceleration due to gravity, are always directed downward (toward the center of the earth), regardless of how the object happens to be moving at the moment. Whether 'downward' is called 'positive' or 'negative' is completely up to you, and depends only on how you have defined the coordinate directions for your experiment or observation.