Current and voltage readings taken on the far right of a meter's scale provide greater inaccuracy that readings taken from mid scale on the meter.
Accuracy
Resistance is probably the missing word. I = e/R. If R is greater, I is less.
Reason: The common Emitter mode has voltage and current gain better than the other two configurations(CB and CC). i.e it has a current gain greater than that of CC mode and greater voltage gain than that of CB mode.
please provide more detail, what do you mean low voltage? Also its not necessarily the voltage your worried about but the amount of current that can be supplied.
(a) voltage and current readings vary with position along the transmission line, (b) voltage and current are difficult to define in non-TEM transmission lines.
Yes. As long as the load stays the same. Voltage equals the resistance of the load times the current or amperage. Or , in this case, as an example, if the load is the same, the voltage is 240 and current is 10 amps. At 120 volts, the current is 20 amps. Current x resistance(or the load)=voltage. With simple math, the equation can be moved around.
Its purpose is to provide approximately the same voltage to a load as what is input to the amplifier, but at a much greater current. In other words, it has no voltage gain, but it does have current gain.
The readings on an ammeter indicate the current being drawn by a load in a circuit. This load is basically a resistance to current flow. The higher the resistance, the lower the current. The supply voltage has a direct effect on current flow. The higher the voltage applied, the higher the current will be. So the readings will vary on the ammeter according to fluctuations in load and or resistance of the circuit and the applied voltage.
...what readings? current? voltage? power? lux?
true
If two ideal sources of unequal voltage are connected in parallel the higher voltage will provide a majority of the current (a two percent difference in voltage would provide an additional 5% of the current) and (in the case of batteries) the larger would provide charging current, quickly draining it.
EMF is electromotive force. It is another name for voltage. Voltage is electric potential in joules per coulomb. Current is electric flow, in amperes. Amperes are coulombs per second. Voltage and current are not the same thing, and "emf current", or "voltage current" does not make sense.
The current is greater than or equal to (6) divided by (the effective resistance of the circuit).
A current source varies the output voltage to maintain the desired current. A voltage source has a constant output regardless of the current draw (up to the capacity of the supply, of course).
Batteries produce DC because the potential difference is determined by the chemical reaction inside the battery. This voltage is constant.
Resistance is probably the missing word. I = e/R. If R is greater, I is less.
Reason: The common Emitter mode has voltage and current gain better than the other two configurations(CB and CC). i.e it has a current gain greater than that of CC mode and greater voltage gain than that of CB mode.
If the applied voltage is greater than maximum forward voltage, the diode will get damaged..