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An R-L series circuit has a power factor of 86 percent How many degrees are the voltage and current out of phase with each other?
Wiki User
∙ 13y ago
If you have access to a calculator: Click cos-1 then .86 to get an answer of 30.6834
Wiki User
∙ 13y ago
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How many degrees are the current and voltage out of phase in a pure capacitive circuit?
In a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
In a pure inductance circuit the current lags the voltage by what degree?
90 degrees
Why the voltage drop across inductance and voltage drop across capacitance is greater than source voltage in series resonance circuit?
The reason for the total voltage drops across the capacitance and inductance IN AN AC CIRCUIT has to do with the different phase angles of the voltages.First, current is the same value and same phase angle everywhere in a series circuit. But, voltage across a capacitor lags current by 90 degrees (capacitor current leads voltage). Next, voltage across a pure inductance leads current by 90 degrees (inductor current lags voltage).The rule that all voltages in a series circuit have to add to the supply voltage still applies, but in this case, the voltage drops are added VECTORALLY, not arithmetically. If you were to graph this addition, you would show any resistance voltage in phase with the current, the capacitor voltage at -90 degrees to the current and the inductor voltage at +90 degrees to the current, for a phase difference between them of 180 degrees, cancelling each other out.In a series resonant circuit, the impedances of the capacitor and inductor cancel each other. The only impedance to the flow of current is any resistance in the circuit. Since real-life inductors always have some resistance, at least there is always some resistance in a series resonant circuit.
If voltage changes in a ac circuit what happens to current?
Voltage attempts to make a current flow, and current will flow if the circuit is complete. It is possible to have voltage without current, but current cannot flow without voltage. The answer is "yes",voltage remains the same as current moves through the circuit.As the voltage remains constant, current increases in the circuit.
If voltage is increased in a circuit what happens to current series and parallel respectively?
In this case current flows from a high voltage to a lower voltage in a circuit.
How many degrees are the current and voltage out of phase in a pure capacitive circuit?
In a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
In a pure inductance circuit the current lags the voltage by what degree?
90 degrees
How does the potential difference across the electric circuit affect current?
In a very simple way. As long as nothing changes in the circuit, the current that flows from the power supply or battery into the circuit is directly proportional to the voltage of the supply. -- If you double the voltage across the ends of the circuit, the current will double. -- If you turn the voltage up to 3.4027 times its original value, the current will increase to 3.4027 times its original value. -- If you decrease the voltage by 81.7 percent, the current will decrease by 81.7 percent.
Why the voltage drop across inductance and voltage drop across capacitance is greater than source voltage in series resonance circuit?
The reason for the total voltage drops across the capacitance and inductance IN AN AC CIRCUIT has to do with the different phase angles of the voltages.First, current is the same value and same phase angle everywhere in a series circuit. But, voltage across a capacitor lags current by 90 degrees (capacitor current leads voltage). Next, voltage across a pure inductance leads current by 90 degrees (inductor current lags voltage).The rule that all voltages in a series circuit have to add to the supply voltage still applies, but in this case, the voltage drops are added VECTORALLY, not arithmetically. If you were to graph this addition, you would show any resistance voltage in phase with the current, the capacitor voltage at -90 degrees to the current and the inductor voltage at +90 degrees to the current, for a phase difference between them of 180 degrees, cancelling each other out.In a series resonant circuit, the impedances of the capacitor and inductor cancel each other. The only impedance to the flow of current is any resistance in the circuit. Since real-life inductors always have some resistance, at least there is always some resistance in a series resonant circuit.
What is phase between voltage and current in a pure inductive circuit?
The phase angle between voltage and current in a purely inductive circuit, under ideal circumstances where there is no resistance at all, is 90 degrees.
Does the current lead or lag the voltage in a series A C circuit containing a large value of capacitance?
ICE current leads the voltage by 90 degrees.
What is the relationship among voltage circuit and resistance in a circuit?
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Compare the phase relationship between the voltage and current in a purely resistive circuit and an RL circuit?
In a pure resistive circuit the voltage and current are in phase. In an inductive circuit they are fro zero to 180 degrees out of phase. If they are in phase the Power Factor is 1 and 180 degrees the PF is zero. The exact amount of the phase difference depends on the specific circuit.
If voltage changes in a ac circuit what happens to current?
Voltage attempts to make a current flow, and current will flow if the circuit is complete. It is possible to have voltage without current, but current cannot flow without voltage. The answer is "yes",voltage remains the same as current moves through the circuit.As the voltage remains constant, current increases in the circuit.
If voltage is increased in a circuit what happens to current series and parallel respectively?
In this case current flows from a high voltage to a lower voltage in a circuit.
What is the relationship among voltage current and resistance in a circuit?
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
What is a relationship among voltage current and resistance in a circuit?
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
